제출 #609822

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
609822		duality	DNA 돌연변이 (IOI21_dna)	C++17	100 / 100	43 ms	7428 KiB

dna

#define DEBUG 0

#include <bits/stdc++.h>
using namespace std;

#if DEBUG
// basic debugging macros
int __i__,__j__;
#define printLine(l) for(__i__=0;__i__<l;__i__++){cout<<"-";}cout<<endl
#define printLine2(l,c) for(__i__=0;__i__<l;__i__++){cout<<c;}cout<<endl
#define printVar(n) cout<<#n<<": "<<n<<endl
#define printArr(a,l) cout<<#a<<": ";for(__i__=0;__i__<l;__i__++){cout<<a[__i__]<<" ";}cout<<endl
#define print2dArr(a,r,c) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<a[__i__][__j__]<<" ";}cout<<endl;}
#define print2dArr2(a,r,c,l) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<setw(l)<<setfill(' ')<<a[__i__][__j__]<<" ";}cout<<endl;}

// advanced debugging class
// debug 1,2,'A',"test";
class _Debug {
    public:
        template<typename T>
        _Debug& operator,(T val) {
            cout << val << endl;
            return *this;
        }
};
#define debug _Debug(),
#else
#define printLine(l)
#define printLine2(l,c)
#define printVar(n)
#define printArr(a,l)
#define print2dArr(a,r,c)
#define print2dArr2(a,r,c,l)
#define debug
#endif

// define
#define MAX_VAL 999999999
#define MAX_VAL_2 999999999999999999LL
#define EPS 1e-6
#define mp make_pair
#define pb push_back

// typedef
typedef unsigned int UI;
typedef long long int LLI;
typedef unsigned long long int ULLI;
typedef unsigned short int US;
typedef pair<int,int> pii;
typedef pair<LLI,LLI> plli;
typedef vector<int> vi;
typedef vector<LLI> vlli;
typedef vector<pii> vpii;
typedef vector<plli> vplli;

// ---------- END OF TEMPLATE ----------
#include "dna.h"

int pre[100001][3][3],num[3][3];
int pos(char c) {
    if (c == 'A') return 0;
    else if (c == 'C') return 1;
    else return 2;
}
void init(string a,string b) {
    int i,n = a.size();
    for (i = 0; i < n; i++) {
        memcpy(pre[i+1],pre[i],sizeof(pre[i]));
        pre[i+1][pos(a[i])][pos(b[i])]++;
    }
}
int get_distance(int x,int y) {
    int i,j;
    for (i = 0; i < 3; i++) {
        for (j = 0; j < 3; j++) num[i][j] = pre[y+1][i][j]-pre[x][i][j];
    }
    int ans = 0;
    for (i = 0; i < 3; i++) {
        j = (i+1) % 3;
        int m = min(num[i][j],num[j][i]);
        ans += m,num[i][j] -= m,num[j][i] -= m;
    }
    if ((num[0][1] != num[1][2]) || (num[1][2] != num[2][0])) return -1;
    else ans += 2*num[0][1];
    if ((num[1][0] != num[2][1]) || (num[2][1] != num[0][2])) return -1;
    else ans += 2*num[1][0];
    return ans;
}

• Subtask 1: 21 / 21
• Subtask 2: 22 / 22
• Subtask 3: 13 / 13
• Subtask 4: 28 / 28
• Subtask 5: 16 / 16