이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<deque>
#include<queue>
#include<vector>
#include<algorithm>
#include<iostream>
#include<set>
#include<cmath>
#include<tuple>
#include<string>
//#include<chrono>
#include<functional>
#include<iterator>
#include<random>
#include<unordered_set>
#include<array>
#include<map>
#include<iomanip>
#include<assert.h>
#include<bitset>
#include<stack>
using namespace std;
typedef long long int llint;
typedef long double lldo;
#define mp make_pair
#define mt make_tuple
#define pub push_back
#define puf push_front
#define pob pop_back
#define pof pop_front
#define fir first
#define sec second
#define res resize
#define ins insert
#define era erase
/*
cout<<setprecision(20)
cin.tie(0);
ios::sync_with_stdio(false);
*/
const llint mod=1e9+7;
const llint big=2.19e15+1;
const long double pai=3.141592653589793238462643383279502884197;
const long double eps=1e-15;
template <class T,class U>void mineq(T& a,U b){if(a>b){a=b;}}
template <class T,class U>void maxeq(T& a,U b){if(a<b){a=b;}}
llint gcd(llint a,llint b){if(a%b==0){return b;}else return gcd(b,a%b);}
//llint lcm(llint a,llint b){return a/gcd(a,b)*b;}
template<class T> void SO(T& ve){sort(ve.begin(),ve.end());}
template<class T> void REV(T& ve){reverse(ve.begin(),ve.end());}
template<class T>llint LBI(vector<T>&ar,T in){return lower_bound(ar.begin(),ar.end(),in)-ar.begin();}
template<class T>llint UBI(vector<T>&ar,T in){return upper_bound(ar.begin(),ar.end(),in)-ar.begin();}
#include"robots.h"
int wee(int A,int T,int X[],int W[]){
static int wa[100001]={0};
int i,ans=0;
for(i=0;i<T;i++){wa[X-upper_bound(X,X+A,W[i])+A]++;}
if(wa[0]>0){return -1;}
for(i=1;i<=A;i++){wa[i]+=wa[i-1];maxeq(ans,(i-1+wa[i])/i);}
return ans;
}
int putaway(int A,int B,int T,int X[],int Y[],int W[],int S[]){
sort(X,X+A);
sort(Y,Y+B);
if(B==0){return wee(A,T,X,W);}
int i,j,ans=0;
static int wa[1001][1001]={0};
for(i=0;i<T;i++){
wa[X-upper_bound(X,X+A,W[i])+A][Y-upper_bound(Y,Y+B,S[i])+B]++;
}
if(wa[0][0]>0){return -1;}
for(i=0;i<A;i++){for(j=0;j<=B;j++){wa[i+1][j]+=wa[i][j];}}
for(i=0;i<=A;i++){for(j=0;j<B;j++){wa[i][j+1]+=wa[i][j];}}
for(i=0;i<=A;i++){
for(j=0;j<=B;j++){
//cout<<wa[i][j]<<" ";
if(i+j==0){continue;}
maxeq(ans,(i+j-1+wa[i][j])/(i+j));
}
//cout<<endl;
}
return ans;
}
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