제출 #590510

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
590510		karrigan	Xylophone (JOI18_xylophone)	C++14	0 / 100	2 ms	308 KiB

xylophone

#include<bits/stdc++.h>
#include <xylophone.h>
#define fastio ios_base::sync_with_stdio(false);cin.tie(nullptr);
using namespace std;
int a[5009];
int pos[5009];
void solve(int n){
for (int i=1;i<=n;i++){
    pos[i]=0;
}
int l=1,r=n;
int pos1=1;
while (l<=r){
    int mid=(l+r)/2;
    int dd=query(mid,n);
    if (dd==n-1){
        l=mid+1;
        pos1=mid;
    }
    else {
        r=mid-1;
    }
}
a[pos1]=1;
pos[1]=1;
answer(pos1,1);
a[pos1+1]=query(pos1,pos1+1)+1;
pos[a[pos1+1]]=1;
answer(pos1+1,a[pos1+1]);
if (pos1>1){
a[pos1-1]=query(pos1-1,pos1)+1;
pos[a[pos1-1]]=1;
answer(pos1-1,a[pos1-1]);
}   
for (int i=pos1+2;i<=n;i++){
        int d=query(i-1,i);
        if (a[i-1]+d>n){
            a[i]=a[i-1]-d;
        }
        else if (a[i-1]-d<0){
            a[i]=a[i-1]+d;
        }
        if (a[i-1]+d<=n&&a[i-1]-d>0){
            if (pos[a[i-1]+d]==1){
                a[i]=a[i-1]-d;
            }
            else if (pos[a[i-1]-d]==1){
                a[i]=a[i-1]+d;
            }
            else if (pos[a[i-1]-d]==0&&pos[a[i-1]+d]==0){
                int rr=query(i-2,i);
                int l1=a[i-1]-d;
                if (max({l1,a[i-1],a[i-2]})-min({l1,a[i-1],a[i-2]})==rr){
                     a[i]=a[i-1]-d;
                }
                else {
                     a[i]=a[i-1]+d;
                }
            }
        }
        pos[a[i]]=1;
        answer(i,a[i]);
}
for (int i=pos1-2;i>=1;i--){
     int d=query(i,i+1);
        if (a[i+1]+d>n){
            a[i]=a[i+1]-d;
        }
        else if (a[i+1]-d<0){
            a[i]=a[i+1]+d;
        }
        if (a[i+1]+d<=n&&a[i+1]-d>0){
            if (pos[a[i+1]+d]==1){
                a[i]=a[i+1]-d;
            }
            else if (pos[a[i+1]-d]==1){
                a[i]=a[i+1]+d;
            }
            else if (pos[a[i+1]-d]==0&&pos[a[i+1]+d]==0){
                int rr=query(i+2,i);
                int l1=a[i+1]-d;
                if (max({l1,a[i+1],a[i+2]})-min({l1,a[i+1],a[i+2]})==rr){
                     a[i]=a[i+1]-d;
                }
                else {
                     a[i]=a[i+1]+d;
                }
            }
        }
        pos[a[i]]=1;
        answer(i,a[i]);
}
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 36
• Subtask 3: 0 / 53