This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define ii pair<int, int>
using namespace std;
int a[100001], t[400004], lazy[400004], k[100001];
int t2[400004];
void build(int v, int tl, int tr){
if(tl == tr){
t[v] = 1; t2[v] = k[tl];
return;
}
int tm = (tl + tr) >> 1;
build(v * 2, tl, tm); build(v * 2 + 1, tm + 1, tr);
t[v] = t[v * 2] + t[v * 2 + 1];
t2[v] = max(t2[v * 2], t2[v * 2 + 1]);
}
void push(int v){
if(lazy[v] != 1) return;
t[v * 2] = 0;
lazy[v * 2] = lazy[v];
t[v * 2 + 1] = 0;
lazy[v * 2 + 1] = lazy[v];
lazy[v] = 0;
}
void ins(int v, int tl, int tr, int l, int r, int val){
if(l > r) return;
if(tl == l && tr == r){
t[v] = 0;
lazy[v] = 1;
return;
}
push(v);
int tm = (tl + tr) >> 1;
ins(v * 2, tl, tm, l, min(r, tm), val);
ins(v * 2 + 1, tm + 1, tr, max(l, tm + 1), r, val);
t[v] = t[v * 2] + t[v * 2 + 1];
return;
}
int query(int v, int tl, int tr, int l, int r){
if(l > r) return 0;
if(tl == l && tr == r) return t[v];
push(v);
int tm = (tl + tr) >> 1;
return query(v * 2, tl, tm, l, min(r, tm)) + query(v * 2 + 1, tm + 1, tr, max(l, tm + 1), r);
}
int query_max(int v, int tl, int tr, int l, int r){
if(l > r) return INT_MIN;
if(tl == l && tr == r) return t2[v];
int tm = (tl + tr) >> 1;
return max(query_max(v * 2, tl, tm, l, min(r, tm)), query_max(v * 2 + 1, tm + 1, tr, max(l, tm + 1), r));
}
vector<ii> v1[100001];
vector<int> v2[100001];
int val[100001], fwt[100001];
int nS[100001], nE[100001];
int query_f(int v){
int ret = 0;
v++;
for(; v > 0; v -= (v & -v)) ret += fwt[v];
return ret;
}
void ins_f(int v, int a){
v++;
for(; v <= 100000; v += (v & -v)){
fwt[v] += a;
}
}
int GetBestPosition(int N, int C, int R, int *K, int *S, int *E) {
for(int i = 0; i < N; i++) k[i] = K[i];
build(1, 0, N - 1);
for(int i = 0; i < C; i++){
int l = 0, r = N - 1;
while(l < r){
int mid = (l + r) >> 1;
int q = query(1, 0, N - 1, 0, mid);
if(q >= S[i] + 1) r = mid;
else l = mid + 1;
}
int head = l, diff = E[i] - S[i] + 1; r = N - 1;
while(l < r){
int mid = (l + r) >> 1;
int q = query(1, 0, N - 1, head, mid);
if(q >= diff) r = mid;
else l = mid + 1;
}
int tail = l;
l = 0; r = N - 1;
while(l < r){
int mid = (l + r) >> 1;
int q = query(1, 0, N - 1, 0, mid);
if(q >= S[i]) r = mid;
else l = mid + 1;
}
head = S[i] == 0 ? 0 : l + 1;
v1[head].push_back({tail, i}); v2[tail + 1].push_back(i);
ins(1, 0, N - 1, head, tail - 1, 0);
val[i] = query_max(1, 0, N - 1, head, tail - 1);
nS[i] = head; nE[i] = tail;
}
int ans = 0, pos = 0;
priority_queue<ii, vector<ii>, greater<ii>> pq;
for(int i = 0; i < N; i++){
while(!pq.empty() && pq.top().second < i){
pq.pop();
}
for(auto x : v2[i]) ins_f(x, -1);
for(auto x : v1[i]){
if(val[x.second] > R) pq.push({x.second, x.first});
ins_f(x.second, 1);
}
int new_ans;
if(!pq.empty()) new_ans = max(ans, query_f(pq.top().first) - 1);
else new_ans = max(ans, query_f(100000));
if(new_ans > ans){
ans = new_ans; pos = i;
}
}
return pos;
}
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