Submission #57596

#TimeUsernameProblemLanguageResultExecution timeMemory
57596kimjg1119Parrots (IOI11_parrots)C++17
17 / 100
5 ms1744 KiB
#include <stdio.h>
#include "encoder.h"
#include "encoderlib.h"

void encode(int N, int M[])
{
  int i;
  int a[8];
  for(i=0; i<N; i++)
  {
      a[i]=M[i]+i*100;
  }
  for(i=0; i<N; i++)
    send(a[i]);
    return;
}
#include <stdio.h>
#include "decoder.h"
#include "decoderlib.h"

void decode(int N, int L, int X[])
{
    int i, b, temp1, temp2;
    int temp[8];
    for(i=0; i<L; i++)
    {
        temp1=X[i]%100;
        temp2=X[i]/100;
        temp[temp2]=temp1;
    }
    for(i=0; i<L; i++)
    {
        b = temp[i];
        output(b);
    }
}

Compilation message (stderr)

encoder.cpp: In function 'void encode(int, int*)':
encoder.cpp:13:3: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   for(i=0; i<N; i++)
   ^~~
encoder.cpp:15:5: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
     return;
     ^~~~~~
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