답안 #57415

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
57415 2018-07-15T01:41:20 Z Benq 호화 벙커 (IZhO13_burrow) C++14
0 / 100
2000 ms 18684 KB
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>

using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;

typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;

template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;

#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)

#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()

const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;

template<int SZ> struct DSU {
    int par[SZ], sz[SZ];
    DSU() {
        F0R(i,SZ) par[i] = -1, sz[i] = 1;
    }
    
    int get(int x) { // path compression
        if (par[x] != x) par[x] = get(par[x]);
        return par[x];
    }
    
    bool unite(int x, int y) { // union-by-rank
        x = get(x), y = get(y);
        if (x == y) return 0;
        if (sz[x] < sz[y]) swap(x,y);
        sz[x] += sz[y], par[y] = x;
        return 1;
    }
};

int n,m,k,cur[1000];
int g[1000][1000];
ll ans = 0;

void solve(int x) {
    vpi v;
    F0R(i,n) v.pb({cur[i]-x,i});
    sort(v.rbegin(),v.rend());
    
    DSU<1000> D = DSU<1000>();
    for (auto a: v) {
        D.par[a.s] = a.s;
        if (a.s > 0 && D.par[a.s-1] != -1) D.unite(a.s,a.s-1);
        if (a.s < n-1 && D.par[a.s+1] != -1) D.unite(a.s,a.s+1);
        ans = max(ans,a.f*(ll)D.sz[D.get(a.s)]);
    }
}

int get(int lo) {
    ans = 0;
    F0R(i,n) cur[i] = m;
    F0Rd(j,m) {
        F0R(i,n) if (g[i][j] < lo) cur[i] = j;
        solve(j);
    }
    return ans;
}

int main() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> n >> m >> k;
    F0R(i,n) F0R(j,m) cin >> g[i][j];
    int lo = 1, hi = 1000000000;
    while (lo < hi) {
        int mid = (lo+hi+1)/2;
        if (get(mid) >= k) lo = mid;
        else hi = mid-1;
    }
    cout << lo << " " << get(lo);
}

/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
*/
# 결과 실행 시간 메모리 Grader output
1 Correct 2 ms 504 KB Output is correct
2 Correct 3 ms 620 KB Output is correct
3 Correct 4 ms 732 KB Output is correct
4 Correct 3 ms 732 KB Output is correct
5 Correct 6 ms 976 KB Output is correct
6 Correct 7 ms 1108 KB Output is correct
7 Correct 16 ms 1108 KB Output is correct
8 Correct 26 ms 1264 KB Output is correct
9 Correct 42 ms 1820 KB Output is correct
10 Correct 109 ms 2172 KB Output is correct
11 Correct 271 ms 2896 KB Output is correct
12 Correct 111 ms 4144 KB Output is correct
13 Correct 138 ms 4144 KB Output is correct
14 Correct 373 ms 4848 KB Output is correct
15 Correct 367 ms 5308 KB Output is correct
16 Correct 367 ms 6532 KB Output is correct
17 Correct 428 ms 7240 KB Output is correct
18 Correct 1029 ms 10644 KB Output is correct
19 Correct 1215 ms 12756 KB Output is correct
20 Execution timed out 2055 ms 18684 KB Time limit exceeded
21 Halted 0 ms 0 KB -