제출 #572421

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
572421		piOOE	Cubeword (CEOI19_cubeword)	C++17	100 / 100	958 ms	11376 KiB

cubeword

#include <bits/stdc++.h>

using namespace std;

#define sz(x) ((int)size(x))
#define all(x) begin(x), end(x)
#define trace(x) cout << #x << ": " << (x) << endl;

typedef long long ll;

mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());

int rand(int l, int r) { return (int) ((ll) rnd() % (r - l + 1)) + l; }

const int N = 8, A = 62, L = 8, mod = 998244353;
const ll infL = 3e18;

int g[N][3] = {{1, 2, 4},
               {0, 3, 5},
               {0, 3, 6},
               {1, 2, 7},
               {0, 5, 6},
               {1, 4, 7},
               {2, 4, 7},
               {3, 5, 6}};

int n;
int cnt[L][A][A], dp2[A][A][A], dp7[A][A][A], dp1[A][A][A], dp4[A][A][A];
int ans = 0;
int len = 0;

int get(char c) {
    if ('a' <= c && c <= 'z') {
        return c - 'a';
    }
    if ('A' <= c && c <= 'Z') {
        return (c - 'A') + 26;
    }
    return (c - '0') + 52;
}

int main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    cin >> n;
    vector<string> stt;
    for (int i = 0; i < n; ++i) {
        string s;
        cin >> s;
        string ss = s;
        reverse(all(ss));
        if (ss != s)
            stt.push_back(ss);
        stt.push_back(s);
    }
    sort(all(stt));
    stt.resize(unique(all(stt)) - begin(stt));
    for (string s: stt) {
        ++cnt[sz(s) - 3][get(s[0])][get(s.back())];
    }
    for (len = 0; len < L; ++len) {
        for (int x0 = 0; x0 < A; ++x0) {
            for (int x3 = 0; x3 < A; ++x3) {
                for (int x6 = 0; x6 < A; ++x6) {
                    ll sum = 0;
                    for (int x = 0; x < A; ++x) {
                        sum += cnt[len][x][x0] * cnt[len][x][x3] * cnt[len][x][x6];
                    }
                    dp2[x0][x3][x6] = dp7[x0][x3][x6] = dp1[x0][x3][x6] = dp4[x0][x3][x6] = sum % mod;
                }
            }
        }
        for (int x0 = 0; x0 < A; ++x0) {
            for (int x3 = 0; x3 < A; ++x3) {
                for (int x5 = 0; x5 < A; ++x5) {
                    for (int x6 = 0; x6 < A; ++x6) {
                        ans = (ans + dp4[x0][x5][x6] * (ll) dp7[x3][x5][x6] % mod * dp1[x0][x3][x5] % mod *
                                     dp2[x0][x3][x6]) % mod;
                    }
                }
            }
        }
    }
    cout << ans;
    return 0;
}

• Subtask 1: 21 / 21
• Subtask 2: 29 / 29
• Subtask 3: 34 / 34
• Subtask 4: 16 / 16