이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define sz(x) ((int)size(x))
#define all(x) begin(x), end(x)
#define trace(x) cout << #x << ": " << (x) << endl;
typedef long long ll;
mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());
int rand(int l, int r) { return (int) ((ll) rnd() % (r - l + 1)) + l; }
const int N = 10000, Q = 101;
const ll infL = 3e18;
int a[N], n, l, ans[N][Q];
int count(int i, int j) {
if (i == j) return 0;
int aans = 0;
for (int id = 0; id < l; ++id) {
aans += (a[i + id] != a[j + id]);
}
return aans;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n >> l;
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
int q;
cin >> q;
vector<pair<int, int>> k(q);
vector<int> ord(q);
for (int i = 0; i < q; ++i) {
cin >> k[i].first;
k[i].second = i;
}
sort(all(k));
for (int i = 0; i < q; ++i)
ord[k[i].second] = i;
k.emplace_back(N + 2, -1);
for (int i = n - l - 1; i > -1; --i) {
int ct = count(i, n - l);
int pnt = lower_bound(all(k), make_pair(ct, -1)) - begin(k);
ans[i][pnt] += 1;
ans[n - l][pnt] += 1;
for (int j = 1; j <= i; ++j) {
ct = ct + (a[i - j] != a[n - l - j]) - (a[i - j + l] != a[n - j]);
while (k[pnt].first < ct)
++pnt;
while (pnt && k[pnt - 1].first >= ct)
--pnt;
ans[i - j][pnt] += 1;
ans[n - l - j][pnt] += 1;
}
}
for (int i = 0; i <= n - l; ++i) {
for (int j = 1; j < q; ++j)
ans[i][j] += ans[i][j - 1];
}
for (int i = 0; i < q; ++i) {
for (int j = 0; j <= n - l; ++j) {
cout << ans[j][ord[i]] << " ";
}
cout << '\n';
}
return 0;
}
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