이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define MASK(i) (1LL << (i))
#define BIT(x, i) ((x >> (i)) & 1)
#define fi first
#define se second
#define ll long long
#define task "name"
const int oo = 1e9 + 7;
const ll loo = (ll)1e18 + 7;
const int MOD = 1e9 + 7;
const int N = 1e5 + 3;
const int BASE = 10;
template <typename T1, typename T2> bool minimize(T1 &a, T2 b)
{
if (a > b) {a = b; return true;} return false;
}
template <typename T1, typename T2> bool maximize(T1 &a, T2 b)
{
if (a < b) {a = b; return true;} return false;
}
int n;
double a[N], b[N];
int main()
{
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
//freopen(task".inp" , "r" , stdin);
//freopen(task".out" , "w" , stdout);
cin >> n;
for (int i = 1; i <= n; i++) cin >> a[i] >> b[i];
sort(a + 1, a + 1 + n, greater<double>());
sort(b + 1, b + 1 + n, greater<double>());
double sum_a = 0, sum_b = 0, ans = 0;
int i = 1, j = 1;
while(i <= n || j <= n)
{
if(i <= n && sum_a <= sum_b) sum_a += a[i++];
else if(j <= n && sum_b < sum_a) sum_b += b[j++];
else break;
maximize(ans, min(sum_a, sum_b) - i - j + 2);
}
cout << fixed << setprecision(4) << ans;
return 0;
}
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