제출 #570431

#제출 시각아이디문제언어결과실행 시간메모리
570431MohammadAghilXylophone (JOI18_xylophone)C++14
100 / 100
131 ms440 KiB
#include <bits/stdc++.h> #include "xylophone.h" // #pragma GCC optimize ("Ofast,unroll-loops") // #pragma GCC target ("avx2") using namespace std; typedef long long ll; typedef pair<long double, ll> pp; #define er(args ...) cerr << __LINE__ << ": ", err(new istringstream(string(#args)), args), cerr << endl #define per(i,r,l) for(int i = (r); i >= (l); i--) #define rep(i,l,r) for(int i = (l); i < (r); i++) #define all(x) x.begin(), x.end() #define sz(x) (int)(x).size() #define pb push_back #define ss second #define ff first void err(istringstream *iss){}template<typename T,typename ...Args> void err(istringstream *iss,const T &_val, const Args&...args){string _name;*iss>>_name;if(_name.back()==',')_name.pop_back();cerr<<_name<<" = "<<_val<<", ",err(iss,args...);} mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const ll mod = 998244353, maxn = 5e5 + 5, lg = 10, inf = ll(1e9) + 5; ll pw(ll a,ll b,ll md=mod){if(!b)return 1;ll k=pw(a,b>>1ll);return k*k%md*(b&1ll?a:1)%md;} void solve(int n){ vector<int> d(n-1); rep(i,0,n-1) d[i] = query(i+1, i+2); vector<int> cr(n); cr[1] = d[0]; rep(i,2,n){ int t = query(i-1,i+1); if(cr[i-2] < cr[i-1]){ if(t == cr[i-1]+d[i-1]-cr[i-2]) cr[i] = cr[i-1] + d[i-1]; else cr[i] = cr[i-1] - d[i-1]; }else{ if(t == cr[i-2]-(cr[i-1]-d[i-1])) cr[i] = cr[i-1] - d[i-1]; else cr[i] = cr[i-1] + d[i-1]; } } int p1 = min_element(all(cr)) - begin(cr), p2 = max_element(all(cr)) - begin(cr); if(p1 > p2) rep(i,0,n) cr[i] = -cr[i]; int mn = *min_element(all(cr)); rep(i,0,n) cr[i] += 1 - mn, answer(i+1, cr[i]); } // int main(){ // cin.tie(0) -> sync_with_stdio(0); // int n = sz(a); // vector<int> d(n-1); // rep(i,0,n-1) d[i] = query(i+1, i+2); // vector<int> cr(n); cr[1] = d[0]; // rep(i,2,n){ // int t = query(i-1,i+1); // if(cr[i-2] < cr[i-1]){ // if(t == cr[i-1]+d[i-1]-cr[i-2]) cr[i] = cr[i-1] + d[i-1]; // else cr[i] = cr[i-1] - d[i-1]; // }else{ // if(t == cr[i-2]-(cr[i-1]-d[i-1])) cr[i] = cr[i-1] - d[i-1]; // else cr[i] = cr[i-1] + d[i-1]; // } // } // int p1 = min_element(all(cr)) - begin(cr), p2 = max_element(all(cr)) - begin(cr); // if(p1 > p2) rep(i,0,n) cr[i] = -cr[i]; // int mn = *min_element(all(cr)); // rep(i,0,n) cr[i] += 1 - mn; // rep(i,0,n) cout << cr[i] << " \n"[i==n-1]; // return 0; // }
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