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답안 #569274

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
569274 2022-05-27T08:10:03 Z inksamurai 푸드 코트 (JOI21_foodcourt) C++17
0 / 100
 68 ms 25444 KB 
#include <bits/stdc++.h>
// cut here
#ifdef _MSC_VER
#include <intrin.h>
#endif
 
namespace atcoder {
 
namespace internal {
 
int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}
 
int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}
 
}  // namespace internal
 
}  // namespace atcoder
 
 
namespace atcoder {
 
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    segtree(int n) : segtree(std::vector<S>(n, e())) {}
    segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }
 
    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }
 
    S get(int p) {
        assert(0 <= p && p < _n);
        return d[p + size];
    }
 
    S prod(int l, int r) {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;
 
        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }
 
    S all_prod() { return d[1]; }
 
    template <bool (*f)(S)> int max_right(int l) {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }
 
    template <bool (*f)(S)> int min_left(int r) {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }
 
  private:
    int _n, size, log;
    std::vector<S> d;
 
    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
 
}  // namespace atcoder
// cut here 
#define int long long
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
#define rng(i,x,n) for(int i=x;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define vec(...) vector<__VA_ARGS__>
#define _3z2QF2y ios::sync_with_stdio(0),cin.tie(0)
typedef long long ll;
using pii=pair<int,int>;
using vi=vector<int>;
void print(){cout<<'\n';}
template<class h,class...t>
void print(const h&v,const t&...u){cout<<v<<' ',print(u...);}
// e

int op(int l,int r){return l+r;}
int e(){return 0;}

signed main(){
_3z2QF2y;
	int n,m,q;
	cin>>n>>m>>q;
	vi bel(q,-1);
	vec(vec(tuple<int,int,int>)) adqry(n);
	vec(vec(pii)) qry(n);
	rep(i,q){
		int t;
		cin>>t;
		if(t==1){
			int l,r,k;
			cin>>l>>r>>bel[i]>>k;
			adqry[l-1].emplace_back(i,k,1);
			if(r<n) adqry[r].emplace_back(i,k,-1);
		}else if(t==2){
			assert(0);
		}else{
			int j,c;
			cin>>j>>c;
			qry[j-1].pb({c,i});
		}
	}
	vi pns(q);
	atcoder::segtree<int,op,e> seg(n+11);
	rep(i,n){
		for(auto &[j,k,t]:adqry[i]){
			if(t==1){
				seg.set(j,k);
			}else{
				seg.set(j,0);
			}
		}
		for(auto &[b,j]:qry[i]){
			int l=0,r=n-1;
			int c=-1;
			while(l<=r){
				int m=(l+r)>>1;
				if(seg.prod(0,m+1)>=b){
					c=m,r=m-1;
				}else{
					l=m+1;
				}
			}
			if(c!=-1 and c<=j){
				pns[j]=bel[c];
			}
		}
	}
	rep(i,q){
		if(bel[i]!=-1) continue;
		cout<<pns[i]<<"\n";
	}
//
	return 0;
}

Subtask #1
0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1 ms 596 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #2
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1 ms 596 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #3
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 5 ms 7644 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #4
0 / 21.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 18 ms 25444 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #5
0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1 ms 596 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #6
0 / 13.0

# 결과 실행 시간 메모리 Grader output
1 Correct 68 ms 8284 KB Output is correct
2 Runtime error 49 ms 15772 KB Execution killed with signal 6
3 Halted 0 ms 0 KB -

Subtask #7
0 / 26.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1 ms 596 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -

Subtask #8
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 1 ms 596 KB Execution killed with signal 6
2 Halted 0 ms 0 KB -