제출 #565404

#제출 시각아이디문제언어결과실행 시간메모리
565404TomkeMonkeDNA 돌연변이 (IOI21_dna)C++17
100 / 100
38 ms6900 KiB
#include <bits/stdc++.h> #include "dna.h" using namespace std; const int MAXN = 1e5 + 7; int slowo1[MAXN]; int slowo2[MAXN]; int pref[MAXN][3][3]; void init(string a, string b) { int n = a.size(); // zamiana znakow na liczby for (int i = 0; i < n; i++) { if (a[i] == 'A') slowo1[i + 1] = 0; if (a[i] == 'T') slowo1[i + 1] = 1; if (a[i] == 'C') slowo1[i + 1] = 2; if (b[i] == 'A') slowo2[i + 1] = 0; if (b[i] == 'T') slowo2[i + 1] = 1; if (b[i] == 'C') slowo2[i + 1] = 2; } // liczenie sum prefiksowych for (int i = 1; i <= n; i++) { for (int c1 = 0; c1 < 3; c1++) { for (int c2 = 0; c2 < 3; c2++) { // jezeli mamy c1 w slowo1 oraz c2 w slowo2 if ((slowo1[i] == c1) && (slowo2[i] == c2)) pref[i][c1][c2] = pref[i - 1][c1][c2] + 1; else pref[i][c1][c2] = pref[i - 1][c1][c2] + 0; } } } } int get_distance(int x, int y) { x = x + 1; y = y + 1; int AT = pref[y][0][1] - pref[x - 1][0][1]; int TA = pref[y][1][0] - pref[x - 1][1][0]; int TC = pref[y][1][2] - pref[x - 1][1][2]; int CT = pref[y][2][1] - pref[x - 1][2][1]; int CA = pref[y][2][0] - pref[x - 1][2][0]; int AC = pref[y][0][2] - pref[x - 1][0][2]; // jezeli mamy tyle samo A, T, C w obu podslowach if ((AT + AC == TA + CA) && (TA + TC == AT + CT)) { int wynik = min(AT, TA) + min(TC, CT) + min(CA, AC); wynik += 2 * abs(AT - TA); return wynik; } else { return -1; } }
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