이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define debug printf
#define ff first
#define ss second
#define mk make_pair
#define lp(i,a,b) for(int i = a ; i < b ; i++)
#define pii pair<int,int>
#define pb push_back
#define all(x) x.begin(),x.end()
#define sz(x) (int)(x.size())
const int LOG = 20 ;
const int MAXN = 1e5+10 ;
using namespace std ;
using namespace __gnu_pbds ;
#define ordered_set tree<pii, null_type,less<pii>, rb_tree_tag,tree_order_statistics_node_update>
int currNode ;
int dsu[MAXN*2] , lvl[MAXN*2] ;
int dp[LOG][MAXN*2] ;
int getLca(int x, int y){
if(x == y) return x ;
if(lvl[x] < lvl[y]) swap(x,y) ;
for(int i = LOG-1 ; i >= 0 ; i-- )
if(dp[i][x] && lvl[dp[i][x]] >= lvl[y])
x = dp[i][x] ;
for(int i = LOG-1 ; i >= 0 ; i-- ){
if(dp[i][x] == dp[i][y]) continue ;
x = dp[i][x] ;
y = dp[i][y] ;
}
return dp[0][x] ;
}
int GetBestPosition(int N, int C, int R, int *K, int *s, int *e)
{
ordered_set o_set ;
for(int i = 0 ; i < N ; i++ ) o_set.insert(make_pair(i,i)) ;
currNode = N-1 ;
for(int i= 0 ; i < C ; i++ ){
auto l = o_set.find_by_order(s[i]) ;
int K = e[i]-s[i]+1 , aux = l->first;
++currNode ;
while(K--){
dp[0][l->second] = currNode ;
l = o_set.erase(l) ;
}
o_set.insert(make_pair(aux, currNode)) ;
}
for(int i = currNode-1 ; i >= 0 ; i-- )
lvl[i] = lvl[ dp[0][i] ]+1 ;
for(int i = 1 ; i < LOG ; i++ )
for(int j = 0 ; j <= currNode ; j++ )
if(dp[i-1][j]) dp[i][j] = dp[i-1][dp[i-1][j]] ;
vector<int> maiorDir ;
for(int i = N-2 ; i >= 0 ; i-- ){
if(K[i] > R) maiorDir.push_back(i) ;
}
int idEsq = -1 ;
int ans = 0 , pos = 0 ;
for(int i = 0 ; i < N ; i++ ){
int idRight = -1 ;
while(!maiorDir.empty() && maiorDir.back() < i ) maiorDir.pop_back() ;
if(!maiorDir.empty()) idRight = maiorDir.back() ;
int ans1 = lvl[i] , ans2 = lvl[i] ;
if(idEsq != -1 ) ans1 -= lvl[getLca(idEsq,i)]+1 ;
if(idRight != -1 ) ans2 -= lvl[getLca(idRight+1, i)]+1 ;
if(min(ans1,ans2) > ans){
pos = i ;
ans = min(ans1, ans2) ;
}
if(K[i] > R) idEsq = i ;
}
/*for(int i = 0 ; i < currNode ; i++ ){
cout << i << " -> " << dp[0][i] << endl ;
} */
//cout << ans << endl ;
return pos ;
}
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