제출 #560589

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
560589		Vanilla	DNA 돌연변이 (IOI21_dna)	C++17	100 / 100	51 ms	8712 KiB

dna

#include <bits/stdc++.h>
#include <fstream>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
struct custom_hash {static uint64_t splitmix64(uint64_t x) {x += 0x9e3779b97f4a7c15;x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;x = (x ^ (x >> 27)) * 0x94d049bb133111eb;return x ^ (x >> 31);}size_t operator()(uint64_t x) const {static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();return splitmix64(x + FIXED_RANDOM);}};
// string __fname = ""; ifstream in (__fname + ".in"); ofstream out (__fname + ".out"); 
// #define cin in 
// #define cout out
#define int64 long long
#define uint64 unsigned long long
#define x first
#define y second
#define pb push_back
#define pii pair <int, int> 
#define pii64 pair <int64, int64>
#define db(x) cout << "> " << #x << ": " << (x) << "\n"
#define qr queries()
#define yn(x) if (x) {ctn("Yes");}else {ctn("No");}
void solve(int);
void queries(){int n;cin >> n;for (int i = 1; i <= n; i++) solve(i);}
template<class T>T ceildiv(T a, T b) {return a / b + !!(a % b);}
template<class T>T gcd (T a, T b){return (b ? gcd(b, a % b): a);}
template<class T>T lcm (T a, T b){return a * b / gcd(a, b);}
// // // // // // // // // // // // // // // // // // // // // // 
/*                  TEMPLATE - VANILLA                         */
// // // // // // // // // // // // // // // // // // // // // //
const int ddx[] = {-1, -1, 0, 1, 1, 1, 0, -1};
const int ddy[] = {0, 1, 1, 1, 0, -1, -1, -1};
const int dx[] = {-1, 0, 1, 0};
const int dy[] = {0, 1, 0, -1};
const double pi = 3.14159265359;
const double eps = 1e-6;
const int64 hash_inv = 940594066;
const int64 hash_p = 101;
const int64 mod = 1e9 + 7;
const int maxn = 2e5 + 2;
string base = "ACT";
int pref_a [maxn][3];
int pref_b [maxn][3];
int pref [maxn][3][3];
int diff [maxn];
int n;

void solve(int id){
    
    return;
}

void init (string a, string b) {
    n = a.size();
    for (int i = 1; i <= n; i++){
        for (int j = 0; j < 3; j++){
            pref_a[i][j] = pref_a[i-1][j] + (a[i-1] == base[j]);
            pref_b[i][j] = pref_b[i-1][j] + (b[i-1] == base[j]);
            for (int k = 0; k < 3; k++){
                pref[i][j][k] = pref[i-1][j][k] + (a[i-1] == base[j] && b[i-1] == base[k]);
            }
        }
    }
}

int get_distance(int x, int y) {
    x++;
    y++;
    for (int i = 0; i < 3; i++){
        if (pref_a[y][i] - pref_a[x-1][i] != pref_b[y][i] - pref_b[x-1][i]) 
            return -1;
    }
    int rs = 0, oth = 0;
    for (int i = 0; i < 3; i++){
        for (int j = i + 1; j < 3; j++){
            int n1 = pref[y][i][j] - pref[x-1][i][j];
            int n2 = pref[y][j][i] - pref[x-1][j][i];
            if (n1 < n2) swap(n1, n2);
            rs+=n2;
            oth+= n1 - n2;
        }
    }
    assert(oth % 3 == 0);
    return rs + oth / 3 * 2;
}


// int main(){
//     ios_base::sync_with_stdio(0); cin.tie(0); cout << fixed; cout << setprecision(10); 
//     init("ACATACAT", "CAACTATA");
//     cout << get_distance(1, 6);
//     // init("ACTC", "CACT");
//     // cout << get_distance(1, 4);
//     return 0;
// }

• Subtask 1: 21 / 21
• Subtask 2: 22 / 22
• Subtask 3: 13 / 13
• Subtask 4: 28 / 28
• Subtask 5: 16 / 16