oj.uz

답안 #560341

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
560341 2022-05-11T10:09:20 Z kartel 사탕 분배 (IOI21_candies) C++17
38 / 100
 5000 ms 57440 KB 
#include <bits/stdc++.h>

//#include "grader.cpp"
#include "candies.h"

#define F first
#define S second
#define pb push_back
#define sz(x) (int)x.size()
#define el "\n"
#define all(x) (x).begin(), (x).end()
using namespace std;
typedef long long ll;

struct st_beats {
    struct node {
        ll mx, mn;
        ll D, Dx;

        node() {
            mx = mn = D = 0;
            Dx = -2e9;
        }

        node operator +(node other) {
            node ret;

            ret.mx = max(mx, other.mx);
            ret.mn = min(mn, other.mn);
            return ret;
        }

        void mrg(node &a, node &b) {
            node x = a + b;
            mx = x.mx; mn = x.mn;
        }

        void add() {
            mx += D; mn += D;
        }

        void updL() {
            mx = mn = Dx;
            Dx = -2e9;
        }
    };

    vector <node> t;
    int n, h;

    st_beats() {}

    void init(int _n, int _h) {
        t.resize(8 * _n);
        for (int i = 0; i < sz(t); i++) {
            t[i] = node();
        }
        h = _h;
        n = _n;
    }

    void push(int v) {
        if (t[v].D) {
            t[v].add();
            t[v * 2].D += t[v].D;
            t[v * 2 + 1].D += t[v].D;
            t[v].D = 0;
        }
    }

    void pushL(int v) {
        if (t[v].Dx != -2e9) {
            t[v * 2].Dx = t[v].Dx;
            t[v * 2 + 1].Dx = t[v].Dx;
            t[v * 2].D = t[v * 2 + 1].D = 0;

            t[v].updL();
        }
    }

    void psh(int v) {
        pushL(v);
        push(v);
    }

    void upd(int v, int l, int r, int tl, int tr, int val) {
        psh(v);
        if (l > r || tl > tr || tl > r || l > tr) {
            return;
        }
        int md = (l + r) >> 1;
        if (l >= tl && r <= tr) {
            t[v].D += val;
            psh(v);
            return;
        }
        upd(v * 2, l, md, tl, tr, val);
        upd(v * 2 + 1, md + 1, r, tl, tr, val);
        t[v].mrg(t[v * 2], t[v * 2 + 1]);
    }

    void upd(int v, int l, int r, int x) {
        psh(v);

        if (t[v].mn > h) {
            t[v].Dx = h;
            psh(v);
            return;
        }
        if (t[v].mx < 0) {
            t[v].Dx = 0;
            psh(v);
            return;
        }

        if (l == r || (t[v].mn >= 0 && t[v].mx <= h)) {
            return;
        }

        int md = (l + r) >> 1;
        upd(v * 2, l, md, 0);
        upd(v * 2 + 1, md + 1, r, 0);
        t[v].mrg(t[v * 2], t[v * 2 + 1]);
    }

    void upd(int l, int r, int val) {
        upd(1, 0, n - 1, l, r, val);

        upd(1, 0, n - 1, 0);
    }

    int get(int v, int l, int r, int ps) {
        psh(v);
        if (l == r) {
            return t[v].mx;
        } else {
            int md = (l + r) >> 1;
            if (ps <= md) {
                return get(v * 2, l, md, ps);
            }
            return get(v * 2 + 1, md + 1, r, ps);
        }
    }

    int get(int x) {
        return get(1, 0, n - 1, x);
    }
} stb;

struct st_min {
    vector <ll> t;
    int n;

    st_min() {}

    void build(int v, int l, int r, vector <ll> &a) {
        if (l == r) {
            t[v] = abs(a[l]);
            return;
        } else {
            int md = (l + r) >> 1;
            build(v * 2, l, md, a);
            build(v * 2 + 1, md + 1, r, a);
            t[v] = min(t[v * 2], t[v * 2 + 1]);
        }
    }

    void init(vector <ll> &a) {
        n = sz(a);
        t.resize(8 * n);
        build(1, 0, n - 1, a);
    }

    void upd(int v, int l, int r, int ps, ll val) {
        if (l == r) {
            t[v] = val;
            return;
        } else {
            int md = (l + r) >> 1;
            if (ps <= md) {
                upd(v * 2, l, md, ps, val);
            } else {
                upd(v * 2 + 1, md + 1, r, ps, val);
            }
            t[v] = min(t[v * 2], t[v * 2 + 1]);
        }
    }

    int get(int v, int l, int r, ll c) {
        if (t[v] > c) {
            return -1;
        }
        if (l == r) {
            return l;
        }
        int md = (l + r) >> 1;
        int cur = get(v * 2, l, md, c);
        if (cur == -1) {
            return get(v * 2 + 1, md + 1, r, c);
        }
        return cur;
    }

    void upd(int ps, ll val) {
        upd(1, 0, n - 1, ps, val);
    }

    int get(ll c) {
        return get(1, 0, n - 1, c);
    }
};

vector <int> solve_st_beats(vector <int> &c, vector <int> &l, vector <int> &r, vector <int> &v) {
    int n = sz(c), q = sz(l);

    stb.init(n, c[0]);
    for (int i = 0; i < q; i++) {
        stb.upd(l[i], r[i], v[i]);
    }

    vector <int> a(n);
    for (int i = 0; i < n; i++) {
        a[i] = stb.get(i);
    }

    return a;
}

vector <int> solve_offline(vector <int> &c, vector <int> &l, vector <int> &r, vector <int> &v) {
    vector <ll> p = {v[0]};
    int q = sz(l), n = sz(c);
    vector <int> nxt(q, 0);
    set <pair <int, ll> > se;

    auto sg = [&](ll x) {
        if (x < 0) {
            return -1;
        }
        return 1;
    };

    for (int i = 1; i < q; i++) {
        if (sg(p.back()) == sg(v[i])) {
            p.back() += v[i];
        } else {
            p.pb(v[i]);
        }
    }
    if (p[0] < 0) {
        p.erase(p.begin());
    }
    q = sz(p);
    for (int i = 0; i < q; i++) {
        nxt[i] = i + 1;
        se.insert({i, p[i]});
    }

    vector <int> ind(n, 0);
    iota(all(ind), 0);
    sort(all(ind), [&](int i, int j) {return (c[i] < c[j]);});

    st_min tM;
    tM.init(p);

    vector <int> ans(n, 0);
    for (auto i : ind) {
        ll x = c[i];
        int j = tM.get(x);
        while (j != -1) {
            ll new_val = p[j];
            int was = j;
            se.erase({j, p[j]});
            vector <int> pos;
            while (nxt[j] < q && new_val >= 0 && new_val <= x) {
                j = nxt[j];
                pos.pb(j);
                se.erase({j, p[j]});
                new_val += p[j];
            }
            for (auto x : pos) {
                nxt[x] = j;
                tM.upd(x, 0);
            }
            if (was != j) {
                nxt[was] = j;
            }
            se.insert({was, new_val});
            tM.upd(was, abs(new_val));
            if (nxt[j] == q) {
                break;
            }
            j = tM.get(x);
        }
        ll val = se.rbegin() -> S;
        if (val < 0) {
            ans[i] = max(0ll, x + val);
        } else {
            ans[i] = min(x, val);
        }
    }

    return ans;
}

vector <int> distribute_candies(vector <int> c, vector <int> l, vector <int> r, vector <int> v) {
    int n = sz(c), q = sz(l);

    if (n <= 2000 && q <= 2000) {
        vector <int> a(n, 0);

        for (int i = 0; i < q; i++) {
            for (int j = l[i]; j <= r[i]; j++) {
                a[j] += v[i];

                a[j] = max(a[j], 0);
                a[j] = min(a[j], c[j]);
            }
        }
        return a;
    } else {
        bool g = 1;
        for (int i = 0; i < q; i++) {
            g &= (v[i] > 0);
        }

        if (g) {
            vector <ll> pf(n, 0);
            vector <int> a(n, 0);

            for (int i = 0; i < q; i++) {
                pf[l[i]] += v[i];
                if (r[i] + 1 < n) {
                    pf[r[i] + 1] -= v[i];
                }
            }

            for (int i = 1; i < n; i++) {
                pf[i] += pf[i - 1];
            }
            for (int i = 0; i < n; i++) {
                a[i] = min(max(0ll, pf[i]), (ll)c[i]);
            }

            return a;
        } else {
            bool eq_c = 1;

            for (int i = 1; i < n; i++) {
                eq_c &= (c[i] == c[0]);
            }

            if (eq_c) {
                return solve_st_beats(c, l, r, v);
            }
            return solve_offline(c, l, r, v);
        }
    }
}

/*
3
10 15 13

2
0 2  20
0 2 -11

*/

Subtask #1
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 4 ms 372 KB Output is correct

Subtask #2
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 105 ms 8892 KB Output is correct
2 Correct 108 ms 8804 KB Output is correct
3 Correct 96 ms 8804 KB Output is correct

Subtask #3
27.0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 142 ms 5600 KB Output is correct
3 Correct 106 ms 53852 KB Output is correct
4 Correct 396 ms 57416 KB Output is correct
5 Correct 463 ms 57440 KB Output is correct
6 Correct 588 ms 57436 KB Output is correct
7 Correct 422 ms 57436 KB Output is correct

Subtask #4
0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 1 ms 212 KB Output is correct
3 Execution timed out 5074 ms 19020 KB Time limit exceeded
4 Halted 0 ms 0 KB -

Subtask #5
0 / 33.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 4 ms 372 KB Output is correct
6 Correct 105 ms 8892 KB Output is correct
7 Correct 108 ms 8804 KB Output is correct
8 Correct 96 ms 8804 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 142 ms 5600 KB Output is correct
11 Correct 106 ms 53852 KB Output is correct
12 Correct 396 ms 57416 KB Output is correct
13 Correct 463 ms 57440 KB Output is correct
14 Correct 588 ms 57436 KB Output is correct
15 Correct 422 ms 57436 KB Output is correct
16 Correct 1 ms 212 KB Output is correct
17 Correct 1 ms 212 KB Output is correct
18 Execution timed out 5074 ms 19020 KB Time limit exceeded
19 Halted 0 ms 0 KB -