Submission #552840

#	Time	Username	Problem	Language	Result	Execution time	Memory
552840		Theo830	Friend (IOI14_friend)	C++17	0 / 100	3 ms	2004 KiB

friend

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e9;
ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<int,int>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
vector<vll>adj;
ll arr[1005];
int findSample(int n, int confidence[], int host[], int protocol[]){
    adj.assign(n+5,vll());
    ll ans = 0;
    ll c[n][2] = {0};
    ll par[n];
    ll col[n];
    par[0] = col[0] = 0;
    c[0][0]++;
    f(i,0,n){
        arr[i] = confidence[i];
    }
    f(i,1,n){
        ll v = host[i];
        if(protocol[i] == 0){
            adj[v].pb(i);
            adj[i].pb(v);
            par[i] = par[v];
            col[i] = col[v] ^ 1;
            c[par[i]][col[i]]++;
        }
        else if(protocol[i] == 1){
            for(auto x:adj[v]){
                adj[i].pb(x);
                adj[x].pb(i);
            }
            if(!adj[v].empty()){
                par[i] = par[v];
                col[i] = col[v];
                c[par[i]][col[i]]++;
            }
            else{
                par[i] = i;
                col[i] = 0;
                c[par[i]][col[i]]++;
            }
        }
        else{
            for(auto x:adj[v]){
                adj[i].pb(x);
                adj[x].pb(i);
            }
            adj[v].pb(i);
            adj[i].pb(v);
        }
    }
    f(i,0,n){
        ans += max(c[i][0],c[i][1]);
    }
    return ans;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 8
• Subtask 3: 0 / 8
• Subtask 4: 0 / 19
• Subtask 5: 0 / 23
• Subtask 6: 0 / 31