이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "paint.h"
#include <bits/stdc++.h>
using namespace std;
bool dp[105][200005], dp2[105][200005], b[200005], w[200005];
int black[200005], white[200005], diff[200005], d[105];
string ans;
string solve_puzzle(string s, vector<int> c)
{
int n=s.length(), k=c.size(), sum=0;
s.insert(s.begin(), '0');
s.insert(s.end(), '0');
c.insert(c.begin(), 0);
c.insert(c.end(), 0);
if (n==c[1])
{
for (int i=1; i<=n; i++)
ans.push_back('X');
return ans;
}
for (int i=1; i<=n; i++)
{
black[i]=black[i-1]+(s[i]=='X');
white[i]=white[i-1]+(s[i]=='_');
}
for (int i=1; i<=k; i++)
d[i]=d[i-1]+c[i];
dp[0][0]=1;
for (int i=1; i<=n; i++)
dp[0][i]=(!black[i]);
for (int i=1; i<=k; i++)
{
for (int j=d[i]+i-1; j<=n; j++)
{
if (s[j]!='X')
dp[i][j]|=dp[i][j-1];
if (s[j]!='_')
{
if (j==c[i])
{
if (!(white[j]))
dp[i][j]=1;
}
else
{
if (!(white[j]-white[j-c[i]]) && s[j-c[i]]!='X')
dp[i][j]|=dp[i-1][j-c[i]-1];
}
}
}
}
dp2[k+1][n+1]=1;
for (int i=n; i>=1; i--)
dp2[k+1][i]=(!(black[n]-black[i-1]));
for (int i=k; i>=1; i--)
{
for (int j=n-(d[k]-d[i-1]+k-i)+1; j>=1; j--)
{
if (s[j]!='X')
dp2[i][j]|=dp2[i][j+1];
if (s[j]!='_')
{
if (j==n-c[i]+1)
{
if (!(white[n]-white[j-1]))
dp2[i][j]=1;
}
else
{
if (!(white[j+c[i]-1]-white[j-1]) && s[j+c[i]]!='X')
dp2[i][j]|=dp2[i+1][j+c[i]+1];
}
}
}
}
for (int i=1; i<=k; i++)
{
for (int j=1; j<=n-c[i]+1; j++)
{
if (s[j-1]!='X' && s[j+c[i]]!='X' && !(white[j+c[i]-1]-white[j-1]))
{
if (j==1)
{
if (i==1 && dp2[2][c[i]+2])
{
diff[j]++;
diff[j+c[i]]--;
}
}
else if (j==n-c[i]+1)
{
if (dp[k-1][j-2] && i==k)
{
diff[j]++;
diff[j+c[i]]--;
}
}
else
{
if (dp[i-1][j-2] && dp2[i+1][j+c[i]+1])
{
diff[j]++;
diff[j+c[i]]--;
}
}
}
}
}
for (int i=1; i<=n; i++)
{
sum+=diff[i];
b[i]=sum;
}
for (int i=1; i<=n; i++)
{
if (s[i]=='X')
continue;
for (int j=0; j<=k; j++)
{
if (dp[j][i-1] && dp2[j+1][i+1])
{
w[i]=1;
break;
}
}
}
for (int i=1; i<=n; i++)
{
if (b[i] && w[i])
ans.push_back('?');
else if (b[i])
ans.push_back('X');
else
ans.push_back('_');
}
return ans;
}
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