이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include "xylophone.h"
typedef long long ll;
using namespace std;
#define FOR(i, x, y) for(ll i=x; i<y; i++)
#define FORNEG(i, x, y) for(ll i=x; i>y; i--)
#define ordered_set tree<ll, null_type,less_equal<ll>, rb_tree_tag,tree_order_statistics_node_update>
#define fast() ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ll int
ll twodiff[5001];
ll threediff[5001];
ll max(ll x[5001]){
ll maxi = -1000000;
FOR(i,0,5002){
if (x[i]!=0){
maxi = max(maxi, x[i]);
}
}
return maxi;
}
ll min(ll x[5001]){
ll mini = 1000000;
FOR(i,0,5002){
if (x[i]!=0){
mini = min(mini, x[i]);
}
}
return mini;
}
void solve(ll n){
FOR(i,0,5001){
twodiff[i] = 0;
threediff[i] = 0;
}
FOR(i,1,n){
twodiff[i] = query(i, i+1);
}
FOR(i,1,n-1){
threediff[i] = query(i, i+2);
}
FOR(i,2,n){
if (threediff[i] != twodiff[i-1] + twodiff[i]){
twodiff[i] *= twodiff[i-1] / abs(twodiff[i-1]);
}
}
if (max(twodiff) - min(twodiff) >=n){
FOR(i,1,n){
twodiff[i] = abs(twodiff[i]);
}
twodiff[1] *= -1;
FOR(i,2,n){
if (threediff[i] != twodiff[i-1] + twodiff[i]){
twodiff[i] *= twodiff[i-1] / abs(twodiff[i-1]);
}
}
ll sus = min(twodiff);
FOR(i,1,n){
twodiff[i] -= sus-1;
}
FOR(i,2,n){
twodiff[i] += twodiff[i-1];
}
FOR(i,1,n){
answer(i, twodiff[i]);
}
}else{
ll sus = min(twodiff);
FOR(i,1,n){
twodiff[i] -= sus-1;
}
FOR(i,2,n){
twodiff[i] += twodiff[i-1];
}
FOR(i,1,n){
answer(i, twodiff[i]);
}
}
}
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