이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*
* File created on 04/07/2022 at 22:12:14.
* Link to problem:
* Description:
* Time complexity: O()
* Space complexity: O()
* Status: ---
* Copyright: Ⓒ 2022 Francois Vogel
*/
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace std;
using namespace __gnu_pbds;
#define pii pair<int, int>
#define f first
#define s second
#define vi vector<int>
#define all(x) x.begin(), x.end()
#define size(x) (int)((x).size())
#define pb push_back
#define ins insert
#define cls clear
// #define int ll
#define ll long long
#define ld long double
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
const int siz = 5e5+40;
vi find_subset(int start, int end, vi b) {
bitset<siz> knapsack;
knapsack.reset();
knapsack.flip(0);
int ori [siz];
for (int i = 0; i < siz; i++) ori[i] = -1;
bitset<siz> pre, loc;
bool found = false;
for (int i = 0; i < size(b); i++) {
pre = knapsack<<b[i];
loc = (pre^knapsack)⪯
knapsack |= pre;
while (loc.any()) {
int pos = loc._Find_first();
assert(ori[pos] == -1);
ori[pos] = i;
if (start <= pos && pos <= end) {
found = true;
break;
}
loc.flip(pos);
}
if (found) break;
}
vi res;
for (int i = start; i <= end; i++) if (ori[i] != -1) {
int x = i;
while (x > 0) {
res.pb(ori[x]);
x -= b[ori[x]];
}
break;
}
return res;
}
// signed main() {
// cin.tie(0);
// ios_base::sync_with_stdio(0);
// int n, l, u;
// cin >> n >> l >> u;
// vi b(n);
// for (int i = 0; i < n; i++) cin >> b[i];
// vi res = find_subset(l, u, b);
// for (int i : res) cout << i << ' ';
// cout.flush();
// int d = 0;
// d++;
// }
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