This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
template<class T> void check_min(T &a, const T &b){ a = (a < b) ? a : b; }
template<class T> void check_max(T &a, const T &b){ a = (a > b) ? a : b; }
#define a__int128(x) (x).begin(), (x).end()
struct CHT{
struct Line{
__int128 first, second;
int index;
Line(__int128 first, __int128 second, int index): first(first), second(second), index(index){}
};
deque<Line> lines;
__int128 floor_div3(__int128 a, __int128 b) {
__int128 d = a / b;
return d * b == a ? d : d - ((a < 0) ^ (b < 0));
}
__int128 ip(Line l1, Line l2){
__int128 a = l1.second - l2.second;
__int128 b = l2.first - l1.first;
return a / b;
}
__int128 eval(Line l, __int128 x){
return l.first * x + l.second;
}
void add(__int128 k, __int128 b, __int128 index){
while(!lines.empty() && k == lines.back().first){
if(lines.back().second <= b)
lines.pop_back();
else
return;
}
while(lines.size() >= 2 && ip(lines[lines.size() - 2], lines.back()) >= ip(lines.back(), Line(k, b, 0)))
lines.pop_back();
lines.push_back(Line(k, b, index));
}
pair<__int128, int> query(__int128 x){
while(lines.size() >= 2 && eval(lines[0], x) <= eval(lines[1], x))
lines.pop_front();
return {eval(lines.front(), x), lines.front().index};
}
};
const int N = 1e5 + 3;
const int K = 200 + 3;
const __int128 INF = 4e18;
__int128 p[N];
ll a[N], n, k;
__int128 dp[2][N];
int pr[K][N];
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
++k;
for(int i = 1; i <= n; ++i)
cin >> a[i];
for(int i = 1; i <= n; ++i)
p[i] = p[i - 1] + a[i];
for(int i = 1; i <= n; ++i)
dp[0][i] = -INF;
dp[0][n + 1] = 0;
for(int j = 1; j <= k; ++j){
CHT cht;
for(int i = n; i >= 1; --i){
cht.add(-p[i], -p[i] * p[i] + p[i] * p[n] + dp[(j - 1) & 1][i + 1], i);
auto q = cht.query(-p[i - 1]);
dp[j & 1][i] = q.first - p[i - 1] * p[n];
pr[j][i] = q.second;
}
dp[j & 1][n + 1] = -INF;
}
cout << (ll)dp[k & 1][1] << "\n";
int pos = 1;
while(k > 1){
int index = pr[k][pos];
cout << index << " ";
pos = index + 1;
--k;
}
cout << "\n";
}
/*
7 3
4 1 3 4 0 2 3
*/
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