이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// oooo
/*
har chi delet mikhad bebar ~
gitar o ba khodet nabar! ~
;Amoo_Hasan;
*/
#include<bits/stdc++.h>
#pragma GCC optimize("O3,no-stack-protector,unroll-loops")
#pragma GCC target("avx2,fma")
#pragma GCC optimze("Ofast")
using namespace std;
typedef long long ll;
typedef long double ld;
#define Sz(x) int((x).size())
#define All(x) (x).begin(), (x).end()
constexpr ll inf = 1e18, N = 1e6 + 10, mod = 1e9 + 7, pr = 1000696969;
int n, a[N], b[N];
bool mark[N], color[N];
struct node {
int pos;
} x[N << 4];
void change(int l, int r, int ind, int pos, int v) {
if(r - l < 2) {
x[v].pos = pos;
return;
}
int mid = (l + r) / 2;
if(ind < mid) change(l, mid, ind, pos, 2 * v);
else change(mid, r, ind, pos, 2 * v + 1);
if(b[x[2 * v].pos] > b[x[2 * v + 1].pos]) x[v].pos = x[2 * v].pos;
else x[v].pos = x[2 * v + 1].pos;
}
int get(int l, int r, int s, int e, int v) {
if(r <= s || l >= e) return 0;
if(l >= s && r <= e) {
return x[v].pos;
}
int mid = (l + r) >> 1;
int pl = get(l, mid, s, e, 2 * v), pr = get(mid, r, s, e, 2 * v + 1);
if(b[pl] >= b[pr]) return pl;
else return pr;
}
struct node2 {
int pos;
} x2[N << 4];
void change2(int l, int r, int ind, int pos, int v) {
if(r - l < 2) {
x2[v].pos = pos;
return;
}
int mid = (l + r) / 2;
if(ind < mid) change2(l, mid, ind, pos, 2 * v);
else change2(mid, r, ind, pos, 2 * v + 1);
if(a[x2[2 * v].pos] < a[x2[2 * v + 1].pos]) x2[v].pos = x2[2 * v].pos;
else x2[v].pos = x2[2 * v + 1].pos;
}
int get2(int l, int r, int s, int e, int v) {
if(r <= s || l >= e) return 0;
if(l >= s && r <= e) {
return x2[v].pos;
}
int mid = (l + r) >> 1;
int pl = get2(l, mid, s, e, 2 * v), pr = get2(mid, r, s, e, 2 * v + 1);
if(a[pl] <= a[pr]) return pl;
else return pr;
}
void DFS(int x) {
mark[x] = 1;
change(1, 2 * n + 1, a[x], 0, 1);
change2(1, 2 * n + 1, b[x], 0, 1);
while(true) {
int ans = get(1, 2 * n + 1, a[x] + 1, b[x], 1);
if(b[ans] <= b[x]) {
break;
}
color[ans] = 1 - color[x];
DFS(ans);
}
while(true) {
int ans = get2(1, 2 * n + 1, a[x] + 1, b[x], 1);
if(a[ans] >= a[x]) break;
color[ans] = 1 - color[x];
DFS(ans);
}
}
bool cmp(pair<int, int> p1, pair<int, int> p2) {
int cnt1 = 0, cnt2 = 0;
if(p1.second == 0) cnt1 = a[p1.first];
else cnt1 = b[p1.first];
if(p2.second == 0) cnt2 = a[p2.first];
else cnt2 = b[p2.first];
return cnt1 < cnt2;
}
bool cmp2(int i, int j) {
return a[i] < a[j];
}
void mkay(ll &a) {
while(a > mod) a -= mod;
}
int main() {
ios :: sync_with_stdio(0), cin.tie(0);
vector<int> res;
cin >>n;
a[0] = 1e9;
for(int i = 1; i <= n; i++) {
cin >>a[i] >>b[i];
change(1, 2 * n + 1, a[i], i, 1);
change2(1, 2 * n + 1, b[i], i, 1);
}
ll ans = 1;
int colorcnt = 0;
for(int i = 1; i <= n; i++) {
if(mark[i]) continue;
DFS(i);
mkay(ans *= 2);
colorcnt++;
}
vector<int> c[2]; vector<pair<int, int> > vc;
for(int i = 1; i <= n; i++) {
vc.push_back({i, 0});
vc.push_back({i, 1});
}
sort(All(vc), cmp);
for(auto i : vc) {
if(i.second == 0) c[color[i.first]].push_back(i.first);
else {
if(c[color[i.first]].empty() || c[color[i.first]].back() != i.first) {
return cout<<0, 0;
}
c[color[i.first]].pop_back();
}
}
cout<<ans;
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
port_facility.cpp:11: warning: ignoring '#pragma GCC optimze' [-Wunknown-pragmas]
11 | #pragma GCC optimze("Ofast")
|
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |