제출 #533853

#제출 시각아이디문제언어결과실행 시간메모리
533853ArnchPort Facility (JOI17_port_facility)C++17
78 / 100
6061 ms40480 KiB
// oooo /* har chi delet mikhad bebar ~ gitar o ba khodet nabar! ~ ;Amoo_Hasan; */ #include<bits/stdc++.h> #pragma GCC optimize("O3,no-stack-protector,unroll-loops") #pragma GCC target("avx2,fma") #pragma GCC optimze("Ofast") using namespace std; typedef long long ll; typedef long double ld; #define Sz(x) int((x).size()) #define All(x) (x).begin(), (x).end() constexpr ll inf = 1e18, N = 1e6 + 10, mod = 1e9 + 7, pr = 1000696969; int n, a[N], b[N]; bool mark[N], color[N]; struct node { int pos; } x[N << 2]; void change(int l, int r, int ind, int pos, int v) { if(r - l < 2) { x[v].pos = pos; return; } int mid = (l + r) / 2; if(ind < mid) change(l, mid, ind, pos, 2 * v); else change(mid, r, ind, pos, 2 * v + 1); if(b[x[2 * v].pos] > b[x[2 * v + 1].pos]) x[v].pos = x[2 * v].pos; else x[v].pos = x[2 * v + 1].pos; } int get(int l, int r, int s, int e, int v) { if(r <= s || l >= e) return 0; if(l >= s && r <= e) { return x[v].pos; } int mid = (l + r) >> 1; int pl = get(l, mid, s, e, 2 * v), pr = get(mid, r, s, e, 2 * v + 1); if(b[pl] >= b[pr]) return pl; else return pr; } struct node2 { int pos; } x2[N << 2]; void change2(int l, int r, int ind, int pos, int v) { if(r - l < 2) { x2[v].pos = pos; return; } int mid = (l + r) / 2; if(ind < mid) change2(l, mid, ind, pos, 2 * v); else change2(mid, r, ind, pos, 2 * v + 1); if(a[x2[2 * v].pos] < a[x2[2 * v + 1].pos]) x2[v].pos = x2[2 * v].pos; else x2[v].pos = x2[2 * v + 1].pos; } int get2(int l, int r, int s, int e, int v) { if(r <= s || l >= e) return 0; if(l >= s && r <= e) { return x2[v].pos; } int mid = (l + r) >> 1; int pl = get2(l, mid, s, e, 2 * v), pr = get2(mid, r, s, e, 2 * v + 1); if(a[pl] <= a[pr]) return pl; else return pr; } void DFS(int x) { mark[x] = 1; change(1, 2 * n + 1, a[x], 0, 1); change2(1, 2 * n + 1, b[x], 0, 1); while(true) { int ans = get(1, 2 * n + 1, a[x] + 1, b[x], 1); if(b[ans] <= b[x]) { break; } color[ans] = 1 - color[x]; DFS(ans); } while(true) { int ans = get2(1, 2 * n + 1, a[x] + 1, b[x], 1); if(a[ans] >= a[x]) break; color[ans] = 1 - color[x]; DFS(ans); } } bool cmp(pair<int, int> p1, pair<int, int> p2) { int cnt1 = 0, cnt2 = 0; if(p1.second == 0) cnt1 = a[p1.first]; else cnt1 = b[p1.first]; if(p2.second == 0) cnt2 = a[p2.first]; else cnt2 = b[p2.first]; return cnt1 < cnt2; } bool cmp2(int i, int j) { return a[i] < a[j]; } void mkay(ll &a) { while(a > mod) a -= mod; } int main() { ios :: sync_with_stdio(0), cin.tie(0); vector<int> res; cin >>n; a[0] = 1e9; for(int i = 1; i <= n; i++) { cin >>a[i] >>b[i]; change(1, 2 * n + 1, a[i], i, 1); change2(1, 2 * n + 1, b[i], i, 1); } ll ans = 1; int colorcnt = 0; for(int i = 1; i <= n; i++) { if(mark[i]) continue; DFS(i); mkay(ans *= 2); colorcnt++; } vector<int> c[2]; vector<pair<int, int> > vc; for(int i = 1; i <= n; i++) { vc.push_back({i, 0}); vc.push_back({i, 1}); } sort(All(vc), cmp); for(auto i : vc) { if(i.second == 0) c[color[i.first]].push_back(i.first); else { if(c[color[i.first]].empty() || c[color[i.first]].back() != i.first) { return cout<<0, 0; } c[color[i.first]].pop_back(); } } cout<<ans; return 0; }

컴파일 시 표준 에러 (stderr) 메시지

port_facility.cpp:11: warning: ignoring '#pragma GCC optimze' [-Wunknown-pragmas]
   11 | #pragma GCC optimze("Ofast")
      |
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...