이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/**
____ ____ ____ ____ ____
||a |||t |||o |||d |||o ||
||__|||__|||__|||__|||__||
|/__\|/__\|/__\|/__\|/__\|
**/
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int NM_MAX = 2000;
const int C_MAX = NM_MAX * 50;
const ll INF = LLONG_MAX / 2;
struct Computer {
int cores;
int rate;
int price;
};
typedef Computer Customer;
bool operator < (const Computer &u, const Computer &v) {
return u.rate < v.rate;
}
int n, m;
Computer computers[NM_MAX + 2];
Customer customers[NM_MAX + 2];
ll maxProfit[2][C_MAX + 2];
void newComputer (int i) {
maxProfit[0][C_MAX + 1] = -INF;
for (int c = C_MAX; c >= 0; c--) {
ll mx = maxProfit[0][c + 1];
// Skip computer
mx = max(mx, maxProfit[1][c]);
// Buy computer
mx = max(mx, maxProfit[1][max(0, c - computers[i].cores)] - computers[i].price);
maxProfit[0][c] = mx;
}
swap(maxProfit[0], maxProfit[1]);
}
void newCustomer (int i) {
maxProfit[0][C_MAX + 1] = -INF;
for (int c = C_MAX; c >= 0; c--) {
ll mx = maxProfit[0][c + 1];
// Skip customer
mx = max(mx, maxProfit[1][c]);
// Take customer
if (c + customers[i].cores <= C_MAX) {
mx = max(mx, maxProfit[1][c + customers[i].cores] + customers[i].price);
}
maxProfit[0][c] = mx;
}
swap(maxProfit[0], maxProfit[1]);
}
int main () {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> computers[i].cores;
cin >> computers[i].rate;
cin >> computers[i].price;
}
cin >> m;
for (int i = 1; i <= m; i++) {
cin >> customers[i].cores;
cin >> customers[i].rate;
cin >> customers[i].price;
}
sort(computers + 1, computers + n + 1);
sort(customers + 1, customers + m + 1);
for (int c = 1; c <= C_MAX; c++) {
maxProfit[1][c] = -INF;
}
for (int i = m, j = n + 1; i >= 1; i--) {
while (j > 1 && computers[j - 1].rate >= customers[i].rate) {
newComputer(--j);
}
newCustomer(i);
}
cout << maxProfit[1][0] << "\n";
return 0;
}
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