// Knapsack DP is harder than FFT.
#include <bits/stdc++.h>
using namespace std;
typedef int64_t ll; typedef pair<int, int> pii;
#define pb emplace_back
#define AI(x) begin(x),end(x)
#define ff first
#define ss second
#ifdef OWO
#define debug(args...) LKJ("\033[1;32m[ " + string(#args) + " ]\033[0m", args)
template <class I> void LKJ(I&&x) { cerr << x << endl; }
template <class I, class...T> void LKJ(I&&x, T&&...t) { cerr << x << ", "; LKJ(t...); }
template <class I> void OI(I a, I b) { while (a != b) cerr << *a << " \n"[(a = next(a)) == b]; }
#else
#define debug(...) 0
#define OI(...) 0
#endif
struct Frac {
ll a, b;
Frac () = default;
Frac (ll _a, ll _b): a(_a), b(_b) { shrink(); }
void shrink() {
if (a == 0 and b == 0) { b = 1; return; }
ll g = gcd(a, b); a /= g; b /= g;
}
const ll toi() const { return a / b; }
const Frac operator + (const Frac& o) const
{ return Frac(a * o.b + o.a * b, b * o.b); }
const Frac operator - (const Frac& o) const
{ return Frac(a * o.b - o.a * b, b * o.b); }
const Frac operator * (const ll& val) const
{ return Frac(a * val, b); }
const bool operator < (const Frac& o) const
{ return a * o.b < o.a * b; }
};
const int kN = 2002;
int N, L, V[kN][kN];
ll pre[kN][kN];
Frac ori[kN];
Frac f(int i, Frac j) {
ll k = j.toi();
ll sum1 = pre[i][k];
j.a -= k * j.b;
Frac sum2 = j * V[i][k + 1];
sum2.a += sum1 * sum2.b;
return sum2;
}
int solve(const vector<int>& perm) {
vector<Frac> x(1, Frac(0, 1));
int cnt = 0;
for (const int& i: perm) {
Frac need = ori[i] + f(i, x.back());
Frac tmp = f(i, x.back());
if (f(i, Frac(L, 1)) < need)
return cnt;
int k = x.back().toi();
while (f(i, Frac(k + 1, 1)) < need) ++k;
need = need - f(i, Frac(k, 1));
Frac nxt = need;
nxt.b *= V[i][k + 1];
nxt.shrink();
x.emplace_back(nxt.a + k * nxt.b, nxt.b);
++cnt;
}
for (int i = 1; i < N; ++i)
cout << x[i].a << ' ' << x[i].b << '\n';
for (const int& i: perm)
cout << i << " \n"[i == perm.back()];
exit(0);
return N;
}
signed main() {
ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
auto start = chrono::system_clock::now();
cin >> N >> L;
for (int i = 1; i <= N; ++i) {
ori[i] = Frac(0, 1);
for (int j = 1; j <= L; ++j) {
cin >> V[i][j];
pre[i][j] = pre[i][j - 1] + V[i][j];
ori[i].a += V[i][j];
}
ori[i].b = N;
ori[i].shrink();
}
vector<int> perm(N);
iota(AI(perm), 1);
random_device rd;
mt19937 mt(rd());
uniform_int_distribution<int> rnd(1, N);
shuffle(AI(perm), mt);
int lst = solve(perm);
while (true) {
auto cur = chrono::system_clock::now();
std::chrono::duration<double> dur = cur - start;
if (dur.count() > 3.0) break;
int u = rnd(mt), v;
do v = rnd(mt); while (v == u);
swap(perm[u], perm[v]);
int sol = solve(perm);
if (sol < lst or (sol == lst and (mt() & 1)))
swap(perm[u], perm[v]);
lst = sol;
}
return 0;
}
Compilation message
naan.cpp: In function 'int solve(const std::vector<int>&)':
naan.cpp:58:8: warning: variable 'tmp' set but not used [-Wunused-but-set-variable]
58 | Frac tmp = f(i, x.back());
| ^~~
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
0 ms |
332 KB |
Integer parameter [name=P_i] equals to 0, violates the range [1, 2] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
1 ms |
332 KB |
Output is correct |
2 |
Incorrect |
1 ms |
332 KB |
X_i is not increasing |
3 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
0 ms |
332 KB |
Integer parameter [name=P_i] equals to 0, violates the range [1, 2] |
2 |
Halted |
0 ms |
0 KB |
- |