#include <bits/stdc++.h>
#define int long long
using namespace std;
#ifdef LOCAL
ifstream in("in.in");
ofstream out("out.out");
#else
#define in cin
#define out cout
#endif
const int nmax = 100005, inf = (1LL << 60);
int n, k;
vector<int> a, b, v, s;
const int MAX_X = 2000005;
int sum(int l, int r) {
return s[r] - s[l - 1];
}
int sol = inf;
void solve() {
int sep1 = 0, sep2 = n + 1;
/// sep1 is the biggest point so that v[sep1] <= -x, so that number behind sep1
/// is just the number of values that will have an x straight up added to them.
/// sep2 is the smallest number such that v[sep2] >= 0, so that they will all get
/// x added to them
/// between sep1 and sep2, sum will get added number of numbers that are there * x -their sum
/// we also get the top numbers from all of these.
s[0] = 0;
for (int i = 1; i <= n; i++) {
s[i] = s[i - 1] + v[i];
}
auto f = [&](int nr, int x) {
///returns the max that you can take out if you take out the last x values
///from right.
int Left = k - nr, cursum = 0, Right = n - nr + 1;
if (nr > 0) {
cursum += sum(Right, n) + nr * x;
}
if (Left > 0) {
cursum += -sum(1, Left) - Left * x;
}
return cursum;
};
int nr = k;
for (int x = MAX_X; x >= 0; x--) {
while (sep1 <= n && v[sep1 + 1] <= -x) {
sep1++;
}
while (sep2 > 1 && v[sep2 - 1] >= 0) {
sep2--;
}
int curSum = 0;
if (sep2 <= n + 1) {
curSum += sum(sep2, n) + (n - sep2 + 1) * x; /// right
}
if (sep1 >= 1) { // there are SOME elements smaller than -x
curSum += -sum(1, sep1) - sep1 * x;
}
if (sep1 < sep2 - 1) {
curSum += (sep2 - sep1 - 1) * x + sum(sep1 + 1, sep2 - 1);
}
while(nr >= 1 && f(nr - 1, x) > f(nr , x)) {
nr--;
}
int bonus = f(nr, x);
sol = min(sol, curSum - bonus);
}
}
int32_t main() {
in >> n >> k;
a.resize(n + 1);
b.resize(n + 1);
v.resize(n + 1);
s.resize(n + 1);
for (int i = 1; i <= n; i++) {
in >> a[i];
}
for (int i = 1; i <= n; i++) {
in >> b[i];
}
for (int i = 1; i <= n; i++) {
v[i] = a[i] - b[i];
}
sort(v.begin() + 1, v.end());
solve();
for (int i = 1; i <= n; i++) {
v[i] *= -1;
}
sort(v.begin() + 1, v.end());
solve();
out << sol << "\n";
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
30 ms |
204 KB |
Output is correct |
2 |
Correct |
25 ms |
268 KB |
Output is correct |
3 |
Correct |
26 ms |
204 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
92 ms |
3404 KB |
Output is correct |
2 |
Correct |
92 ms |
3420 KB |
Output is correct |
3 |
Correct |
98 ms |
3424 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
102 ms |
3416 KB |
Output is correct |
2 |
Correct |
91 ms |
3424 KB |
Output is correct |
3 |
Correct |
93 ms |
3404 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
98 ms |
3428 KB |
Output is correct |
2 |
Correct |
93 ms |
3428 KB |
Output is correct |
3 |
Correct |
94 ms |
3420 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
82 ms |
3420 KB |
Output is correct |
2 |
Correct |
111 ms |
4816 KB |
Output is correct |
3 |
Correct |
107 ms |
4856 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
115 ms |
3528 KB |
Output is correct |
2 |
Correct |
109 ms |
4784 KB |
Output is correct |
3 |
Correct |
124 ms |
4856 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
100 ms |
3416 KB |
Output is correct |
2 |
Correct |
103 ms |
4828 KB |
Output is correct |
3 |
Correct |
116 ms |
4856 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
116 ms |
3428 KB |
Output is correct |
2 |
Correct |
106 ms |
4816 KB |
Output is correct |
3 |
Correct |
122 ms |
4856 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
114 ms |
3404 KB |
Output is correct |
2 |
Correct |
113 ms |
4852 KB |
Output is correct |
3 |
Correct |
119 ms |
4852 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
114 ms |
3424 KB |
Output is correct |
2 |
Correct |
107 ms |
4860 KB |
Output is correct |
3 |
Correct |
109 ms |
4856 KB |
Output is correct |