Submission #5171

#TimeUsernameProblemLanguageResultExecution timeMemory
5171cki86201초록색 삼각형 (YDX13_green)C++98
0 / 1
1008 ms1352 KiB
#include<stdio.h> #include<algorithm> #include<math.h> typedef long long ll; const double PI = 3.141592653589793238; int x[2020], y[2020], ord[2020]; double an[2020]; int n; bool comp(const int &a,const int &b){return an[a] < an[b];} int main() { scanf("%d",&n); int i, j; for(i=1;i<=n;i++)scanf("%d%d",x+i,y+i); if(n<=2)return printf("0")&0; for(i=1;i<=n;i++)ord[i] = i; double ans = 0; for(i=1;i<=n;i++){ for(j=1;j<=n;j++)an[j] = atan2(y[j] - y[i], x[j] - x[i]); std::sort(ord+1,ord+1+n,comp); ll now[2] = {0,0}; int t = 1; double na = 0; for(j=1;j<=n;j++){ int nj = ord[j]; if(j>1)na -= fmod(an[nj] - an[ord[j-1]] + 2*PI, 2*PI); while(na < PI+1e-10){ now[0] += x[ord[t]] - x[i]; now[1] += y[ord[t]] - y[i]; na += fmod(an[ord[t%n+1]] - an[ord[t]] + 2*PI, 2*PI); t = t%n + 1; } now[0] -= x[nj] - x[i], now[1] -= y[nj] - y[i]; ans += (double)now[1] * (x[nj] - x[i]) - (double)now[0] * (y[nj] - y[i]); } } printf("%.12f",ans/n/(n-1)/(n-2)); return 0; }
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