제출 #514581

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
514581		Theo830	Table Tennis (info1cup20_tabletennis)	C++17	9 / 100	110 ms	21712 KiB

tabletennis

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e9+7;
const ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ii,ll>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
int main(void){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    ll n,k;
    cin>>n>>k;
    ll arr[n+k];
    vll ans[2];
    map<ll,bool>ex;
    f(i,0,n+k){
        cin>>arr[i];
        ex[arr[i]] = 1;
    }
    ll Sum = -1;
    f(i,0,k+1){
        f(j,max(i+1,n-1),n+k){
            ll posa = 0;
            ll sum = arr[i] + arr[j];
            f(u,0,n+k){
                if(ex[arr[u]]){
                    posa++;
                }
            }
            if(posa >= n){
                Sum = sum;
                break;
            }
        }
        if(Sum != -1){
            break;
        }
    }
    f(i,0,n+k){
        if(ex[Sum - arr[i]]){
            ans[0].pb(arr[i]);
            ans[1].pb(Sum - arr[i]);
        }
        if(ans[0].size() == n/2){
            break;
        }
    }
    for(auto x:ans[0]){
        cout<<x<<" ";
    }
    reverse(all(ans[1]));
    for(auto x:ans[1]){
        cout<<x<<" ";
    }
}

컴파일 시 표준 에러 (stderr) 메시지

tabletennis.cpp: In function 'int main()':
tabletennis.cpp:61:26: warning: comparison of integer expressions of different signedness: 'std::vector<long long int>::size_type' {aka 'long unsigned int'} and 'll' {aka 'long long int'} [-Wsign-compare]
   61 |         if(ans[0].size() == n/2){
      |            ~~~~~~~~~~~~~~^~~~~~

• Subtask 1: 0 / 11
• Subtask 2: 0 / 9
• Subtask 3: 0 / 14
• Subtask 4: 0 / 15
• Subtask 5: 9 / 9
• Subtask 6: 0 / 14
• Subtask 7: 0 / 15
• Subtask 8: 0 / 13