Submission #512281

#TimeUsernameProblemLanguageResultExecution timeMemory
512281fatemetmhrPort Facility (JOI17_port_facility)C++17
78 / 100
6116 ms406676 KiB
// ~Be name khoda~ // #include<bits/stdc++.h> using namespace std; typedef long long ll; #define pb push_back #define mp make_pair #define all(x) x.begin(), x.end() #define fi first #define se second #define cl clear #define endll '\n' const int maxn = 1e6 + 10; const int maxn5 = 1e6 + 10; const int maxnt = 4e6 + 10; const int maxn3 = 1e3 + 10; const int mod = 1e9 + 7; const ll inf = 2e18; vector <int> adj, have, adj2[maxn5]; int ty[maxn5], a[maxn5], b[maxn5]; int per1[maxn5], per2[maxn5]; int per1c[maxn5], per2c[maxn5]; bool mark[maxn5]; int seg1[23][maxn5], seg2[23][maxn5]; int pt1[maxnt], pt2[maxnt], bg1[maxnt], bg2[maxnt]; int last1[24], last2[24]; vector <pair<int, int>> av; set <pair<int, int>> seg; int n; inline bool cmp1(int i, int j){return b[i] < b[j];} inline bool cmp2(int i, int j){return a[i] > a[j];} inline bool cmp3(int i, int j){return a[i] < a[j];} inline bool cmp4(int i, int j){return b[i] < b[j];} inline void build1(int l, int r, int v, int lev){ bg1[v] = last1[lev]; pt1[v] = bg1[v]; for(int i = l; i < r; i++) seg1[lev][pt1[v]++] = per1[i]; sort(seg1[lev] + bg1[v], seg1[lev] + pt1[v], cmp1); last1[lev] = pt1[v]; pt1[v]--; if(r - l == 1) return; int mid = (l + r) >> 1; build1(l, mid, v * 2, lev + 1); build1(mid, r, v * 2 + 1, lev + 1); return; } inline void build2(int l, int r, int v, int lev){ bg2[v] = last2[lev]; pt2[v] = bg2[v]; for(int i = l; i < r; i++) seg2[lev][pt2[v]++] = per2[i]; sort(seg2[lev] + bg2[v], seg2[lev] + pt2[v], cmp2); last2[lev] = pt2[v]; pt2[v]--; if(r - l == 1) return; int mid = (l + r) >> 1; build2(l, mid, v * 2, lev + 1); build2(mid, r, v * 2 + 1, lev + 1); return; } inline void get1(int l, int r, int lq, int rq, int val, int v, int lev){ if(rq <= l || r <= lq) return; if(lq <= l && r <= rq){ while(pt1[v] >= bg1[v] && b[seg1[lev][pt1[v]]] >= val){ adj.pb(seg1[lev][pt1[v]]); pt1[v]--; } return; } int mid = (l + r) >> 1; get1(l, mid, lq, rq, val, v * 2, lev + 1); get1(mid, r, lq, rq, val, v * 2 + 1, lev + 1); return; } inline void get2(int l, int r, int lq, int rq, int val, int v, int lev){ if(rq <= l || r <= lq) return; if(lq <= l && r <= rq){ while(pt2[v] >= bg2[v] && a[seg2[lev][pt2[v]]] <= val){ adj.pb(seg2[lev][pt2[v]]); pt2[v]--; } return; } int mid = (l + r) >> 1; get2(l, mid, lq, rq, val, v * 2, lev + 1); get2(mid, r, lq, rq, val, v * 2 + 1, lev + 1); return; } inline int idof1(int val){ int p = lower_bound(per1c, per1c + n, val) - per1c; return p; } inline int idof2(int val){ int p = lower_bound(per2c, per2c + n, val) - per2c; return p; } inline void dfs2(int v){ mark[v] = true; adj.clear(); vector <int> have; get1(0, n, idof1(a[v]), idof1(b[v] + 1), b[v], 1, 0); // laghal get2(0, n, idof2(a[v]), idof2(b[v] + 1), a[v], 1, 0); // hadeaksar for(auto u : adj) adj2[v].pb(u); for(auto u : adj2[v]){ //cout << "e " << v << ' ' << u << endl; if(!mark[u]) dfs2(u); } return; } inline void dfs(int v){ mark[v] = true; for(auto u : adj2[v]) if(!mark[u]){ ty[u] = (ty[v] ^ 1); dfs(u); } return; } inline void check(){ av.clear(); for(auto i : have){ mark[i] = false; av.pb({a[i], i}); av.pb({b[i], i}); } sort(all(av)); seg.clear(); for(auto [u, i] : av){ if(u == a[i]){ seg.insert({a[i], i}); } else{ seg.erase({a[i], i}); auto it = seg.lower_bound(mp(a[i], 0)); if(it != seg.end()){ cout << 0 << endl; exit(0); } } } return; } int main() { ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0); cin >> n; for(int i = 0; i < n; i++){ cin >> a[i] >> b[i]; a[i]--; b[i]--; per1[i] = i; per2[i] = i; } sort(per1, per1 + n, cmp3); sort(per2, per2 + n, cmp4); for(int i = 0; i < n; i++){ per1c[i] = a[per1[i]]; per2c[i] = b[per2[i]]; } build1(0, n, 1, 0); build2(0, n, 1, 0); for(int i = 0; i < n; i++) if(!mark[i]){ dfs2(i); } fill(mark, mark + n + 10, false); int cnt = 0; for(int i = 0; i < n; i++) if(!mark[i]){ ty[i] = 0; dfs(i); cnt++; } for(int i = 0; i < n; i++) if(ty[i] == 0){ have.pb(i); } check(); have.clear(); for(int i = 0; i < n; i++) if(ty[i] == 1) have.pb(i); check(); ll ans = 1; while(cnt--){ ans *= 2; ans %= mod; } cout << ans << endl; }
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