제출 #504127

#제출 시각아이디문제언어결과실행 시간메모리
504127Hacv16Sure Bet (CEOI17_sure)C++17
0 / 100
0 ms332 KiB
#include<bits/stdc++.h> using namespace std; typedef long long ll; typedef pair<int, int> pii; const int MAX = 2e6 + 15; const int INF = 0x3f3f3f3f; const int MOD = 1e9 + 7; #define pb push_back #define sz(x) (int) x.size() #define fr first #define sc second #define mp make_pair #define all(x) x.begin(), x.end() int n; long double a[MAX], b[MAX]; void setIO(){ ios_base::sync_with_stdio(false); cin.tie(NULL); } int main(){ setIO(); cin >> n; for(int i = 0; i < n; i++){ cin >> a[i] >> b[i]; } sort(a, a + n, greater<long double>()); sort(b, b + n, greater<long double>()); int pa = 1, pb = 1; long double sa = a[0], sb = b[0], ans = 0; while(pa != n && pb != n){ if(sa < sb){ sa += a[pa]; pa++; }else{ sb += b[pb]; pb++; } ans = max(ans, min(sa - (pa + pb), sb - (pa + pb))); } cout << setprecision(4) << fixed << ans << endl; return 0; } /* stuff you should look for * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and stay organized * brute force to find pattern? * sort? * graph? * WRITE STUFF DOWN * DON'T GET STUCK ON ONE APPROACH */
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