oj.uz

답안 #501203

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
501203 2022-01-02T15:41:10 Z radal Semiexpress (JOI17_semiexpress) C++14
100 / 100
 469 ms 8908 KB 
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC target("avx2,fma")
#define rep(i,l,r) for (int i = l; i < r; i++)
#define repr(i,r,l) for (int i = r; i >= l; i--)
#define X first
#define Y second
#define pb push_back
#define endl '\n'
#define debug(x) cerr << #x << " : " << x << endl;
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pll;
const long long int N = 7e5+20,mod = 1e9+7,inf = 1e9+10,sq = 400;
inline int mkay(int a,int b){
    if (a+b >= mod) return a+b-mod;
    if (a+b < 0) return a+b+mod;
    return a+b;
}
inline int poww(int n,int k){
    int c = 1;
    while (k){
        if (k&1) c = (1ll*c*n)%mod;
        n = (1ll*n*n)%mod;
        k >>= 1;
    }
    return c;
}
int dp[N][2],n,m,k,a,b,c,r[N],pre[N],ig[N],nxt[N];
ll t,ti[N];
bitset<inf> st;
int main(){
    ios :: sync_with_stdio(0); cin.tie(0);
    cin >> n >> m >> k >> a >> b >> c >> t;
    vector<pair<int,bool>> ve;
    ve.reserve(N);
    vector<int> imp;
    imp.reserve(m);
    int lst = 1;
    ve.pb({0,0});
    rep(i,0,m){
        int x;
        cin >> x;
        ve.pb({x,1});
        imp.pb(x);
    }
    int cnt = 0;
    rep(i,0,m){
        ll tm = 1ll*b*(imp[i]-1),l = imp[i];
        while (tm <= t && (t-tm)/a+l < n && (i < m-1 && (t-tm)/a+l+1 < imp[i+1]) && cnt < k-m+30000){
            int p = (t-tm)/a+l+1;
            if (st[p]) break;
            st[p] = 1;
            ve.pb({p,0});
            tm += 1ll*(p-l)*c;
            l = p;
            cnt++;
        }
        lst = imp[i];
    }
    sort(ve.begin(),ve.end());
    int sz = ve.size()-1;
    lst = 1;
    cnt = 0;
    rep(i,1,sz+1){
        ll tm = 1ll*b*(lst-1);
        if (tm > t){
            pre[i] = pre[i-1]+ve[i].X-ve[i-1].X;
        }
        else{
            int p = (t-tm)/a+lst-ve[i-1].X;
            if (p < 0) p = 0;
            if (p > ve[i].X-ve[i-1].X){
                p = ve[i].X-ve[i-1].X;
            }
            cnt += p;
            pre[i] = pre[i-1]+ve[i].X-ve[i-1].X-p;
            if (1ll*b*(ve[i].X-1) <= t && ve[i].Y && p < ve[i].X-ve[i-1].X){
                cnt++;
                pre[i]--;
            }
        }
        if (ve[i].Y) lst = ve[i].X;
        ti[i] = 1ll*b*(lst-1)+1ll*a*(ve[i].X-lst);
        dp[i][0] = -inf;
    }
    lst = 1;
    rep(i,1,sz+1){
        if (ve[i].Y) lst = ve[i].X;
        ll tm = 1ll*b*(lst-1)+1ll*c*(ve[i].X-lst);
        if (tm > t) r[i] = ve[i].X-1;
        else r[i] = min(1ll*n,(t-tm)/a+ve[i].X);
        if (!ve[i].Y) r[i] = min(r[i],*(lower_bound(imp.begin(),imp.end(),ve[i].X))-1);
        else r[i] = min(r[i],ve[i].X-1);
    }

    repr(i,sz,1){
        ig[i] = lower_bound(r,r+sz+1,ve[i].X)-r-1;
    }
    rep(d,1,k+1){
        int j = (d&1);
        rep(i,1,sz+1){
            if (ve[i].Y) dp[i][j] = dp[i-1][1-j];
            else dp[i][j] = dp[i-1][j];
            if (ti[i] <= t || ve[i].Y || r[i] < ve[i].X){
                if (ve[i].Y) lst = ve[i].X;
                continue;
            }
            int ind = ig[i];
            ll tm = 1ll*b*(lst-1);
            if (tm > t){
                dp[i][j] = max(dp[i][j],dp[ind][1-j]+r[i]-ve[i].X+1);
                continue;
            }
            int p = (t-tm)/a+lst;
            if (p >= ve[i].X) dp[i][j] = max(dp[i][j],dp[ind][1-j]+r[i]-p);
            else dp[i][j] = max(dp[i][j],dp[ind][1-j]+r[i]-ve[i].X+1);
        }
    }
    cout << dp[sz][(k&1)]+cnt-1;
}

Subtask #1
18.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 320 KB Output is correct
2 Correct 0 ms 324 KB Output is correct
3 Correct 1 ms 320 KB Output is correct
4 Correct 0 ms 324 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 0 ms 332 KB Output is correct
8 Correct 0 ms 332 KB Output is correct

Subtask #2
30.0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 320 KB Output is correct
2 Correct 0 ms 324 KB Output is correct
3 Correct 1 ms 320 KB Output is correct
4 Correct 0 ms 324 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 0 ms 332 KB Output is correct
8 Correct 0 ms 332 KB Output is correct
9 Correct 1 ms 324 KB Output is correct
10 Correct 1 ms 332 KB Output is correct
11 Correct 1 ms 332 KB Output is correct
12 Correct 0 ms 324 KB Output is correct
13 Correct 1 ms 324 KB Output is correct
14 Correct 1 ms 324 KB Output is correct
15 Correct 1 ms 332 KB Output is correct
16 Correct 1 ms 332 KB Output is correct
17 Correct 1 ms 332 KB Output is correct
18 Correct 0 ms 332 KB Output is correct

Subtask #3
52.0 / 52.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 320 KB Output is correct
2 Correct 0 ms 324 KB Output is correct
3 Correct 1 ms 320 KB Output is correct
4 Correct 0 ms 324 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 0 ms 332 KB Output is correct
8 Correct 0 ms 332 KB Output is correct
9 Correct 1 ms 324 KB Output is correct
10 Correct 1 ms 332 KB Output is correct
11 Correct 1 ms 332 KB Output is correct
12 Correct 0 ms 324 KB Output is correct
13 Correct 1 ms 324 KB Output is correct
14 Correct 1 ms 324 KB Output is correct
15 Correct 1 ms 332 KB Output is correct
16 Correct 1 ms 332 KB Output is correct
17 Correct 1 ms 332 KB Output is correct
18 Correct 0 ms 332 KB Output is correct
19 Correct 4 ms 460 KB Output is correct
20 Correct 4 ms 460 KB Output is correct
21 Correct 206 ms 1492 KB Output is correct
22 Correct 364 ms 4044 KB Output is correct
23 Correct 469 ms 7044 KB Output is correct
24 Correct 279 ms 8908 KB Output is correct
25 Correct 2 ms 504 KB Output is correct
26 Correct 5 ms 484 KB Output is correct
27 Correct 265 ms 1484 KB Output is correct
28 Correct 273 ms 1484 KB Output is correct
29 Correct 206 ms 2124 KB Output is correct
30 Correct 372 ms 2252 KB Output is correct