제출 #496363

#제출 시각아이디문제언어결과실행 시간메모리
496363armashkaValley (BOI19_valley)C++17
0 / 100
3072 ms31812 KiB
#include <bits/stdc++.h> //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr); #define all(v) v.begin(),v.end() #define pb push_back #define sz size() #define ft first #define sd second using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef unsigned long long ull; const int N = 5e5 + 5; const ll M = 1e8; const ll inf = 1e9; const ll mod = 1e9; const double Pi = acos(-1); ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;} ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;} ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); } bool odd(ll n) { return (n % 2 == 1); } bool even(ll n) { return (n % 2 == 0); } ll n, s, q, e, a[N]; vector <pll> g[N]; pll edge[N]; map <pll, bool> bl; const void solve(/*Armashka*/) { cin >> n >> s >> q >> e; for (int i = 1; i < n; ++ i) { ll w; cin >> edge[i].ft >> edge[i].sd >> w; ll u = edge[i].ft, v = edge[i].sd; g[u].pb({v, w}); g[v].pb({u, w}); } for (int i = 1; i <= s; ++ i) cin >> a[i]; for (int i = 1; i <= q; ++ i) { ll num, start; cin >> num >> start; bl[{edge[num].ft, edge[num].sd}] = 1; queue <ll> q; vector <ll> d(n + 5, inf); q.push(start); d[start] = 0; while (q.sz) { ll v = q.front(); q.pop(); for (auto [to, w] : g[v]) { if (bl[{to, v}] || bl[{v, to}]) continue; if (d[to] > d[v] + w) { d[to] = d[v] + w; q.push(to); } } } if (d[e] != inf) cout << "escaped\n"; else { ll mn = inf; for (int i = 1; i <= s; ++ i) mn = min(mn, d[a[i]]); if (mn == inf) cout << "oo\n"; else cout << mn << "\n"; } } } signed main() { fast; //freopen("divide.in", "r", stdin); //freopen("divide.out", "w", stdout); int tt = 1; //cin >> tt; while (tt --) { solve(); } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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