This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
#define all(v) v.begin(),v.end()
#define pb push_back
#define sz size()
#define ft first
#define sd second
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef unsigned long long ull;
const int N = 5e5 + 5;
const ll M = 1e8;
const ll inf = 1e9;
const ll mod = 1e9;
const double Pi = acos(-1);
ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); }
bool odd(ll n) { return (n % 2 == 1); }
bool even(ll n) { return (n % 2 == 0); }
ll n, s, q, e, a[N];
vector <pll> g[N];
pll edge[N];
map <pll, bool> bl;
const void solve(/*Armashka*/) {
cin >> n >> s >> q >> e;
for (int i = 1; i < n; ++ i) {
ll w;
cin >> edge[i].ft >> edge[i].sd >> w;
ll u = edge[i].ft, v = edge[i].sd;
g[u].pb({v, w});
g[v].pb({u, w});
}
for (int i = 1; i <= s; ++ i) cin >> a[i];
for (int i = 1; i <= q; ++ i) {
ll num, start;
cin >> num >> start;
bl[{edge[num].ft, edge[num].sd}] = 1;
queue <ll> q;
vector <ll> d(n + 5, inf);
q.push(start);
d[start] = 0;
while (q.sz) {
ll v = q.front();
q.pop();
for (auto [to, w] : g[v]) {
if (bl[{to, v}] || bl[{v, to}]) continue;
if (d[to] > d[v] + w) {
d[to] = d[v] + w;
q.push(to);
}
}
}
if (d[e] != inf) cout << "escaped\n";
else {
ll mn = inf;
for (int i = 1; i <= s; ++ i) mn = min(mn, d[a[i]]);
if (mn == inf) cout << "oo\n";
else cout << mn << "\n";
}
}
}
signed main() {
fast;
//freopen("divide.in", "r", stdin);
//freopen("divide.out", "w", stdout);
int tt = 1;
//cin >> tt;
while (tt --) {
solve();
}
}
/*
5 4 4
1 2
3 1
3 4
5 3
4 5 2 3
2 1 3 1
1 3 5
2 3 4 5
2 1 3 1
*/
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