이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define int long long
//#define double long double
#define Nanase_Kurumi_aka_menhera_chan_is_mine ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define pb push_back
#define pi pair<int, int>
#define ALL(i) i.begin(),i.end()
#define gcd(i,j) __gcd(i,j)
#define fi first
#define se second
#define eps 0.00000001
#define ist insert
#define DNE nullptr
//#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math")
//#pragma GCC optimize("O2")
int max(int x,int y){return x>=y?x:y;}
int min(int x,int y){return x>=y?y:x;}
using namespace std;
typedef int ll;
const int N=100005;
const int M=1000005;
const int MOD=1000000007;//998244353;
const int INF=1000000000000000000;//2147483647;
int n,m,k,A,B,C,T;
int s[N],has[N];
int calc(){
int j=1,pre=1,cnt=0;
vector<int> tim(n+5,0);
for (int i=2;i<=n;i++){
tim[i]=tim[i-1]+A;
if (s[j]==i)
tim[i]=min(tim[i],tim[s[j-1]]+(i-s[j-1])*B);
if (tim[i]>T&&tim[pre]+(i-pre)*C<=T&&cnt<k-m){
cnt++;
tim[i]=tim[pre]+(i-pre)*C;
pre=i;
}
if (s[j]==i) pre=i,j++;
}
cnt=0;
for (int i=1;i<=n;i++)
if (tim[i]<=T)
cnt++;
return cnt;
}
inline void sol(){
cin >>n>>m>>k>>A>>B>>C>>T;
for (int i=0;i<m;i++)
cin >>s[i],has[s[i]]=1;
cout <<calc()-1<<'\n';
}
signed main(){
Nanase_Kurumi_aka_menhera_chan_is_mine
int _=1;
//cin >>_;
while (_--) sol();
return 0;
}
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