제출 #492216

#제출 시각아이디문제언어결과실행 시간메모리
492216blue모임들 (IOI18_meetings)C++17
36 / 100
5566 ms304848 KiB
#include "meetings.h" #include <vector> #include <algorithm> #include <iostream> #include <deque> using namespace std; using ll = long long; using vll = vector<ll>; using vi = vector<int>; using pii = pair<int, int>; #define sz(x) (int(x.size())) const int mx = 750'000; const ll INF = 1'000'000'000'000'000'000LL; int N; int Q; vi H; vi L, R; vi M(mx); vi peak_queries[mx]; vi HD; vi lc, rc; vi le, re; vll ans; struct segtree { int l; int r; pii v; segtree* left = NULL; segtree* right = NULL; segtree() { ; } segtree(int L, int R, vi& Z) { l = L; r = R; if(l == r) { v = {Z[l], l}; } else { int m = (l+r)/2; left = new segtree(l, m, Z); right = new segtree(m+1, r, Z); v = max(left->v, right->v); } } pii rangemax(int L, int R) { if(R < l || r < L) return {-1, -1}; else if(L <= l && r <= R) return v; else return max(left->rangemax(L, R), right->rangemax(L, R)); } }; segtree ST; vi subtree; int build_tree(int l, int r) { if(r < l) return -1; int m = ST.rangemax(l, r).second; lc[m] = build_tree(l, m-1); rc[m] = build_tree(m+1, r); if(lc[m] != -1) subtree[m] += subtree[lc[m]]; if(rc[m] != -1) subtree[m] += subtree[rc[m]]; return m; } struct seg { int x1; ll y1; int x2; ll y2; ll get_slope() { if(x2 == x1) return 0; else return (y2-y1)/(x2-x1); } }; struct func { ll lp = 0; deque<seg> d; void inc(ll W) { lp += W; } void push_back(func& K) { for(seg k: K.d) { d.push_back(seg{k.x1, k.y1 + K.lp - lp, k.x2, k.y2 + K.lp - lp}); } } void push_front(func& K) { reverse(K.d.begin(), K.d.end()); for(seg k: K.d) { d.push_front(seg{k.x1, k.y1 + K.lp - lp, k.x2, k.y2 + K.lp - lp}); } } void front_AP(ll a, ll sl) { int xf = d.front().x1; int xb = -1; while(!d.empty()) { ll dy2 = d.front().y2 + lp; int dx2 = d.front().x2; ll dy1 = d.front().y1 + lp; int dx1 = d.front().x1; ll new_y2 = a + sl*(dx2 - xf); if(new_y2 > dy2) break; else if(a > dy1) break; else { xb = max(xb, d.front().x2); d.pop_front(); } } if(!d.empty()) { // cerr << "case X\n"; ll dy1 = d.front().y1 + lp; ll dx1 = d.front().x1; ll new_y1 = a + sl*(dx1 - xf); if(new_y1 <= d[0].y1 + lp) { ll d_sl = (d[0].y2 - d[0].y1)/(d[0].x2 - d[0].x1); int lo = d[0].x1; int hi = d[0].x2; while(lo != hi) { int mid = (lo+hi)/2 + 1; ll mid_y = lp + d[0].y1 + (mid-d[0].x1)*d_sl; ll new_y = a + sl*(mid - xf); if(new_y <= mid_y) lo = mid; else hi = mid-1; } xb = max(xb, lo); d[0].x1 = lo+1; d[0].y1 = d[0].y2 - (d[0].x2 - d[0].x1)*d_sl; } } if(xf <= xb) { d.push_front({xf, a - lp, xb, a+sl*(xb-xf) - lp}); } } }; vector<func*> F(mx); void dfs(int u) { if(u == -1) return; le[u] = re[u] = u; if(lc[u] != -1) { dfs(lc[u]); subtree[u] += subtree[lc[u]]; le[u] = le[lc[u]]; } if(rc[u] != -1) { dfs(rc[u]); subtree[u] += subtree[rc[u]]; re[u] = re[rc[u]]; } for(int q: peak_queries[u]) { int lo = 0; int hi = sz(F[rc[u]]->d) - 1; while(lo != hi) { int mid = (lo+hi)/2; if(F[rc[u]]->d[mid].x2 < R[q]) lo = mid+1; else hi = mid; } auto fr = F[rc[u]]; ll right_ans = fr->lp + fr->d[lo].y1 + fr->d[lo].get_slope()*(R[q] - fr->d[lo].x1); ans[q] = min(ans[q], ll(H[u])*(u - L[q] + 1) + right_ans); } ll left_ct = 1; if(lc[u] != -1) left_ct += subtree[lc[u]]; if(rc[u] != -1) { F[rc[u]]->inc(ll(H[u])*(u - le[u] + 1)); } ll dp_u; if(lc[u] == -1) { dp_u = H[u]; } else { dp_u = H[u] + F[lc[u]]->d.back().y2 + F[lc[u]]->lp; } func ths; ths.d.push_back(seg{u, dp_u, u, dp_u}); if(rc[u] != -1) { F[rc[u]]->front_AP(dp_u + H[u], H[u]); } if(lc[u] == -1 && rc[u] == -1) { F[u]->push_back(ths); } else if(lc[u] == -1) { F[u] = F[rc[u]]; F[u]->push_front(ths); } else if(rc[u] == -1) { F[u] = F[lc[u]]; F[u]->push_back(ths); } else { if(subtree[rc[u]] >= subtree[lc[u]]) { F[u] = F[rc[u]]; F[u]->push_front(ths); F[u]->push_front(*F[lc[u]]); F[lc[u]]->d.clear(); } else { F[u] = F[lc[u]]; F[u]->push_back(ths); F[u]->push_back(*F[rc[u]]); F[rc[u]]->d.clear(); } } } vll minimum_costs(vi H_, vi L_, vi R_) { // for(int f: L_) cerr << "le = " << f << '\n'; //PART 1: PROCESS INPUT H = H_; L = L_; R = R_; N = sz(H); Q = sz(L); // cerr << "queries: \n"; // for(int j = 0; j < Q; j++) cerr << L_[j] << ' ' << R_[j] << '\n'; //PART 2: DISCRETISE HEIGHTS HD = vi(N); vector<pii> P; for(int i = 0; i < N; i++) P.push_back({H[i], i}); sort(P.begin(), P.end()); int ct = 0; for(pii p:P) { ct++; HD[p.second] = ct; } // for(int j = 0; j < Q; j++) cerr << j << " : " << M[j] << '\n'; ans = vll(Q, INF); for(int t = 0; t <= 1; t++) { //PART 3: IDENTIFY PEAK OF EACH QUERY if(t == 1) { reverse(HD.begin(), HD.end()); reverse(H.begin(), H.end()); for(int j = 0; j < Q; j++) { L[j] = N-1 - L[j]; R[j] = N-1 - R[j]; swap(L[j], R[j]); M[j] = N-1 - M[j]; } } for(int i = 0; i < N; i++) { peak_queries[i].clear(); } ST = segtree(0, N-1, HD); for(int j = 0; j < Q; j++) { if(t == 0) M[j] = ST.rangemax(L[j], R[j]).second; if(M[j] == R[j]) { ans[j] = min(ans[j], ll(H[M[j]])*(R[j] - L[j] + 1)); } else peak_queries[M[j]].push_back(j); } lc = rc = vi(N, -1); le = vi(N, 1'000'000'000); re = vi(N, -1); subtree = vi(N, 1); int rt = build_tree(0, N-1); for(int i = 0; i < N; i++) F[i] = new func; dfs(rt); } return ans; }

컴파일 시 표준 에러 (stderr) 메시지

meetings.cpp: In member function 'void func::front_AP(ll, ll)':
meetings.cpp:152:17: warning: unused variable 'dx1' [-Wunused-variable]
  152 |             int dx1 = d.front().x1;
      |                 ^~~
meetings.cpp:169:16: warning: unused variable 'dy1' [-Wunused-variable]
  169 |             ll dy1 = d.front().y1 + lp;
      |                ^~~
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