제출 #489821

#제출 시각아이디문제언어결과실행 시간메모리
489821ignaciocantaGrowing Trees (BOI11_grow)C++14
100 / 100
99 ms2872 KiB
#include <bits/stdc++.h> using namespace std; #include <ext/pb_ds/assoc_container.hpp> using namespace __gnu_pbds; template<class T> using Tree = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>; using tint = long long; using ld = long double; #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) #define trav(a,x) for (auto& a: x) using pi = pair<int,int>; using pl = pair<tint,tint>; using vi = vector<int>; using vpi = vector<pi>; using vpl = vector<pl>; using vvi = vector<vi>; using vl = vector<tint>; using vvl = vector<vl>; using vb = vector<bool>; #define pb push_back #define pf push_front #define rsz resize #define all(x) begin(x), end(x) #define rall(x) x.rbegin(), x.rend() #define sz(x) (int)(x).size() #define ins insert #define f first #define s second #define mp make_pair #define DBG(x) cerr << #x << " = " << x << endl; const int MOD = 1e9+7; const int mod = 998244353; const int MX = 1e5+5; const tint INF = 1e18; const int inf = 1e9; const ld PI = acos(ld(-1)); const ld eps = 1e-5; const int dx[4] = {1, -1, 0, 0}; const int dy[4] = {0, 0, 1, -1}; template<class T> void remDup(vector<T> &v){ sort(all(v)); v.erase(unique(all(v)),end(v)); } template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } bool valid(int x, int y, int n, int m){ return (0<=x && x<n && 0<=y && y<m); } int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } void NACHO(string name = ""){ ios_base::sync_with_stdio(0); cin.tie(0); if(sz(name)){ freopen((name+".in").c_str(), "r", stdin); freopen((name+".out").c_str(), "w", stdout); } } int B[MX]; int n; void upd(int pos, int val){ for(int x = pos; x <= n; x += x&(-x)){ B[x] += val; } } int sum(int pos){ int ret = 0; for(int x = pos; x > 0; x -= x&(-x)){ ret += B[x]; } return ret; } int main(){ NACHO(); int q; cin >> n >> q; vi a(n+1); F0R(i, n){ cin >> a[i+1]; } sort(all(a)); FOR(i, 1, n+1) upd(i, a[i] - a[i-1]); F0R(assa, q){ char t; cin >> t; if(t == 'F'){ int c, h; cin >> c >> h; int low = 0, high = n+1; while(high - low > 1){ int mid = low + (high - low) / 2; if(sum(mid) >= h) high = mid; else low = mid; } int L = high; if(L == n+1) continue; int R = L + c - 1; if(R >= n){ upd(L, 1); continue; } int a_r = sum(R); low = 0, high = n+1; while(high - low > 1){ int mid = low + (high - low) / 2; if(sum(mid) >= a_r) high = mid; else low = mid; } int L2 = high; low = 0, high = n+1; while(high - low > 1){ int mid = low + (high - low) / 2; if(sum(mid) > a_r) high = mid; else low = mid; } int R2 = high - 1; upd(L, 1); upd(L2, -1); upd(R2 - (c - (L2 - L)) + 1, 1); upd(R2 + 1, -1); }else{ int l, r; cin >> l >> r; int low = 0, high = n+1; while(high - low > 1){ int mid = low + (high - low) / 2; if(sum(mid) >= l) high = mid; else low = mid; } int L = high; low = 0, high = n+1; while(high - low > 1){ int mid = low + (high - low) / 2; if(sum(mid) > r) high = mid; else low = mid; } int R = high - 1; cout << max(0, R - L + 1) << "\n"; } } }

컴파일 시 표준 에러 (stderr) 메시지

grow.cpp: In function 'void NACHO(std::string)':
grow.cpp:74:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   74 |         freopen((name+".in").c_str(), "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
grow.cpp:75:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   75 |         freopen((name+".out").c_str(), "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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