제출 #469318

#제출 시각아이디문제언어결과실행 시간메모리
469318Return_0Port Facility (JOI17_port_facility)C++17
0 / 100
1 ms332 KiB
#pragma GCC optimize("Ofast,unroll-loops") // #pragma comment(linker, "/stack:200000000") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,fma,tune=native") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef int ll; typedef long double ld; typedef pair <ll, ll> pll; #ifdef SINA #define dbg(...) __f(#__VA_ARGS__, __VA_ARGS__) template <typename Arg1> void __f(const char* name, Arg1&& arg1) { cout << name << " : " << arg1 << std::endl; } template <typename Arg1, typename... Args> void __f (const char* names, Arg1&& arg1, Args&&... args) { const char* comma = strchr(names + 1, ',');cout.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...); } #define dbg2(x, j, n) cout<< #x << " : "; output((j), (n), x, 1); cout.flush(); #else #define dbg(...) 0 #define dbg2(x, j, n) 0 #endif #define SZ(x) ((ll)((x).size())) #define File(s, t) freopen(s ".txt", "r", stdin); freopen(t ".txt", "w", stdout); #define input(j, n, a) for (int _i = (j); _i < (n)+(j); _i++) cin>> a[_i]; #define output(j, n, a, t) for (int _i = (j); _i < (n)+(j); _i++) cout<< a[_i] << (((t) && _i != (n)+(j)-1)? ' ' : '\n'); #define kill(x) return cout<< (x) << endl, 0 #define cl const ll #define fr first #define sc second #define lc (v << 1) #define rc (lc | 1) #define mid ((l + r) >> 1) #define All(x) (x).begin(), (x).end() cl inf = sizeof(ll) == 4 ? (1e9 + 10) : (3e18), mod = 1e9 + 7, MOD = 998244353; template <class A,class B> ostream& operator << (ostream& out,const pair<A,B>&a){return out<<'('<<a.first<<", "<<a.second<<')';} template <class A> ostream& operator << (ostream& out, const vector<A> &a) { out<< '['; for (int i = -1; ++i < int(a.size());) out<< a[i] << (i + 1 < int(a.size()) ? ", " : ""); return out<<']'; } template <class T, typename _t = less <T> > using Tree = tree <T, null_type, _t, rb_tree_tag, tree_order_statistics_node_update>; cl N = 1e6 + 7; ll par [N], a [N << 1], A [N], B [N], n, _n; vector <ll> vec1, vec2; inline bool check (cl &i, cl &j) { return ((A[i] < A[j] && A[j] < B[i] && B[i] < B[j]) || (A[j] < A[i] && A[i] < B[j] && B[j] < B[i])); } ll root (cl &v) { return par[v] ? par[v] = root(par[v]) : v; } inline bool unite (ll v, ll u) { v = root(v); u = root(u); if (v == u) return false; return par[u] = v, _n--, true; } struct segtree { ll l, r, roo; bool empty; segtree *lt, *rt; inline segtree (cl &L = 1, cl &R = N - 2) : l(L), r(R), roo(0), empty(true) {} void build () { if (l == r) return; lt = new segtree (l, mid); rt = new segtree (mid + 1, r); lt->build(); rt->build(); } void unify (cl &ql, cl &qr, cl &x) { if (r < ql || qr < l || empty) return; if (ql <= l && r <= qr) { if (roo) unite(x, roo); else { lt->unify(ql, qr, x); rt->unify(ql, qr, x); roo = x; } return; } lt->unify(ql, qr, x); rt->unify(ql, qr, x); } void upd (cl &pos, cl &x) { empty = false; if (l == r) { roo = x; return; } if (pos <= lt->r) lt->upd(pos, x); else rt->upd(pos, x); roo = root(lt->roo) == root(rt->roo) ? lt->roo : 0; } } seg; int main () { cin.tie(0)->sync_with_stdio(false); cin>> n; _n = n; for (ll i = 1; i <= n; i++) cin>> A[i] >> B[i], a[A[i]] = i, a[B[i]] = i + n; for (ll i = 1; i <= n + n; i++) { if (a[i] <= n) { if (vec1.empty() || !check(vec1.back(), a[i])) vec1.push_back(a[i]); else if (vec2.empty() || !check(vec2.back(), a[i])) vec2.push_back(a[i]); else kill(0); } else { if (!vec1.empty() && vec1.back() == a[i] - n) vec1.pop_back(); else if (!vec2.empty() && vec2.back() == a[i] - n) vec2.pop_back(); else kill(0); } } seg.r = n + n; seg.build(); for (ll i = 1; i <= n + n; i++) if (a[i] <= n) { seg.upd(B[a[i]], a[i]); seg.unify(A[a[i]], B[a[i]], a[i]); } for (n = 1; _n--; n = (n + n) % mod); cout<< n << endl; cerr<< "\n" __TIMESTAMP__ " - Time elapsed: " << 1000 * clock() / CLOCKS_PER_SEC << "ms\n"; return 0; } /* */
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