제출 #466218

#제출 시각아이디문제언어결과실행 시간메모리
466218Namnamseo여행하는 상인 (APIO17_merchant)C++17
100 / 100
96 ms3324 KiB
#pragma GCC optimize("Ofast") #pragma GCC target("avx2") #include <cstring> #include <iostream> using namespace std; using ll=long long; const int maxn = int(1e2) + 10; const int maxk = int(1e3) + 10; const ll inf = 0x3f3f3f3f * ((1ll<<32)+1); int n, m, knd; int buy[maxn][maxk], sell[maxn][maxk]; ll de[maxn][maxn]; int mxsell[maxn][maxn]; #define Floyd(d) { \ for (int j=1; j<=n; ++j) { \ for (int i=1; i<=n; ++i) for (int k=1; k<=n; ++k) \ d[i][k] = min(d[i][k], d[i][j] + d[j][k]); \ } \ } int main() { cin.tie(0)->sync_with_stdio(0); cin >> n >> m >> knd; n &= 127; for (int i=1; i<=n; ++i) for (int j=1; j<=knd; ++j) { cin >> buy[i][j] >> sell[i][j]; } memset(de, 0x3f, sizeof(de)); for (int i=1; i<=m; ++i) { int f, t, v; cin >> f >> t >> v; de[f][t] = min(de[f][t], ll(v)); } Floyd(de); for (int t=1; t<=knd; ++t) { for (int i=1; i<=n; ++i) if (buy[i][t] != -1) for (int j=1; j<=n; ++j) if (sell[j][t] != -1) { mxsell[i][j] = max(mxsell[i][j], sell[j][t]-buy[i][t]); } } int ql=-1, qr=int(1e9)+10; while (ql+1 < qr) { int c = (ql+qr)/2; static ll dc[maxn][maxn]; for (int i=1; i<=n; ++i) for (int j=1; j<=n; ++j) { if (de[i][j] == inf) dc[i][j] = inf; else dc[i][j] = c*1ll*de[i][j]-mxsell[i][j]; } Floyd(dc); bool loop = false; for (int i=1; i<=n; ++i) if (dc[i][i] <= 0) { loop = true; break; } (loop ? ql : qr) = c; } cout << ql << '\n'; return 0; }
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