이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/// In The Name Of God
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#include <bits/stdc++.h>
#define f first
#define s second
#define pb push_back
#define pp pop_back
#define mp make_pair
#define sz(x) (int)x.size()
#define sqr(x) ((x) * 1ll * (x))
#define all(x) x.begin(), x.end()
#define Kazakhstan ios_base :: sync_with_stdio(0), cin.tie(0), cout.tie(0);
#define nl '\n'
#define ioi exit(0);
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
const int N = (int)5e5 + 7;
const int inf = (int)1e9 + 7;
const int mod = (int)1e9 + 7;
const ll linf = (ll)1e18 + 7;
const ld eps = 1e-4;
const int dx[] = {-1, 0, 1, 0, 1, -1, -1, 1};
const int dy[] = {0, 1, 0, -1, 1, -1, 1, -1};
using namespace std;
int n;
bool bad[N];
double a[N], b[N];
double ans;
void rec(int v = 1, double x = 0, double y = 0) {
if (v > n) {
ans = max(ans, min(x, y));
if (clock() / (double)CLOCKS_PER_SEC > 1.9) cout << setprecision(4) << fixed << ans, ioi
return;
}
if (min(a[v], b[v]) > 2 - eps) rec(v + 1, x + a[v] - 2, y + b[v] - 2);
else rec(v + 1, x, y);
if (!bad[v]) {
rec(v + 1, x + a[v] - 1, y - 1);
rec(v + 1, x - 1, y + b[v] - 1);
}
}
int main() {
#ifdef IOI2018
freopen ("in.txt", "r", stdin);
#endif
Kazakhstan
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i] >> b[i];
}
rec();
cout << setprecision(4) << fixed << ans;
ioi
}
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