oj.uz

답안 #443157

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
443157 2021-07-09T22:43:37 Z ignaciocanta Palindromic Partitions (CEOI17_palindromic) C++14
100 / 100
 389 ms 42392 KB 
#include <bits/stdc++.h>

using namespace std;

//#include <ext/pb_ds/assoc_container.hpp>
//using namespace __gnu_pbds;
//template<class T> using Tree = tree<T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
 
using tint = long long;
using ld = long double;
 
#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)	
 
using pi = pair<int,int>;
using pl = pair<tint,tint>;
using vi = vector<int>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vvi = vector<vi>;
using vl = vector<tint>;
using vb = vector<bool>;
 
#define pb push_back
#define pf push_front
#define rsz resize
#define all(x) begin(x), end(x)
#define rall(x) x.rbegin(), x.rend() 
#define sz(x) (int)(x).size()
#define ins insert
 
#define f first
#define s second
#define mp make_pair
 
#define DBG(x) cerr << #x << " = " << x << endl;
 
const int MOD = 1e9+7; 
const int mod = 998244353;
const int MX = 1e6+5;
const tint INF = 1e9; 
const int inf = 2e8;
const ld PI = acos(ld(-1)); 
const ld eps = 1e-5;
 
const int dx[4] = {1, -1, 0, 0};
const int dy[4] = {0, 0, 1, -1};
 
template<class T> void remDup(vector<T> &v){ 
    sort(all(v)); v.erase(unique(all(v)),end(v));
}
 
template<class T> bool ckmin(T& a, const T& b) {
    return b < a ? a = b, 1 : 0; 
} 
template<class T> bool ckmax(T& a, const T& b) {
    return a < b ? a = b, 1 : 0; 
}
 
bool valid(int x, int y, int n, int m){
    return (0<=x && x<n && 0<=y && y<m);
}
 
int cdiv(int a, int b) { return a/b+((a^b)>0&&a%b); } //redondea p arriba
int fdiv(int a, int b) { return a/b-((a^b)<0&&a%b); } //redondea p abajo
 
void NACHO(string name = ""){
    ios_base::sync_with_stdio(0); cin.tie(0);
    if(sz(name)){
        freopen((name+".in").c_str(), "r", stdin);
        freopen((name+".out").c_str(), "w", stdout);
    }
}

string s;
const tint P = 9973, M1 = 1e9+7, M2 = 1e9+9;
tint hsh1[MX], hsh2[MX], pw1[MX], pw2[MX];

void calc_hash(){
	hsh1[0] = hsh2[0] = pw1[0] = pw2[0] =  1;
	FOR(i, 1, sz(s)+1) pw1[i] = pw1[i-1] * P % M1, pw2[i] = pw2[i-1] * P % M2;
	FOR(i, 1, sz(s)+1){
		hsh1[i] = ((hsh1[i-1] * P) % M1 + s[i-1]) % M1;
		hsh2[i] = ((hsh2[i-1] * P) % M2 + s[i-1]) % M2;
	}
}

tint get_hsh(int l, int r, tint M){
	if(M == M1) return (((hsh1[r+1] - pw1[r-l+1] * hsh1[l] % M) % M) + M) % M;
	else return (((hsh2[r+1] - pw2[r-l+1] * hsh2[l] % M) % M) + M) % M;
}

int main(){
	NACHO();
	int tc; cin >> tc;
	while(tc--){
		cin >> s;
		calc_hash();
		int lst = -1;
		int ret = 0;
		F0R(i, sz(s)){
			if(get_hsh(lst+1, i, M1) == get_hsh(sz(s)-i-1, sz(s)-lst-2, M1) && get_hsh(lst+1, i, M2) == get_hsh(sz(s)-i-1, sz(s)-lst-2, M2)){
				//cout << i << " " << lst << endl;
				++ret;
				lst = i;
			}
		}
		cout << ret << "\n";
	}
}

Compilation message

palindromic.cpp: In function 'void NACHO(std::string)':
palindromic.cpp:73:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   73 |         freopen((name+".in").c_str(), "r", stdin);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
palindromic.cpp:74:16: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   74 |         freopen((name+".out").c_str(), "w", stdout);
      |         ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct
2 Correct 1 ms 332 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 1 ms 332 KB Output is correct
5 Correct 1 ms 332 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct
2 Correct 1 ms 332 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 1 ms 332 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 1 ms 332 KB Output is correct
8 Correct 1 ms 328 KB Output is correct
9 Correct 1 ms 332 KB Output is correct

Subtask #3
25.0 / 25.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct
2 Correct 1 ms 332 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 1 ms 332 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 1 ms 332 KB Output is correct
8 Correct 1 ms 328 KB Output is correct
9 Correct 1 ms 332 KB Output is correct
10 Correct 4 ms 716 KB Output is correct
11 Correct 3 ms 640 KB Output is correct
12 Correct 4 ms 716 KB Output is correct
13 Correct 4 ms 588 KB Output is correct

Subtask #4
40.0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 332 KB Output is correct
2 Correct 1 ms 332 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 1 ms 332 KB Output is correct
5 Correct 1 ms 332 KB Output is correct
6 Correct 1 ms 332 KB Output is correct
7 Correct 1 ms 332 KB Output is correct
8 Correct 1 ms 328 KB Output is correct
9 Correct 1 ms 332 KB Output is correct
10 Correct 4 ms 716 KB Output is correct
11 Correct 3 ms 640 KB Output is correct
12 Correct 4 ms 716 KB Output is correct
13 Correct 4 ms 588 KB Output is correct
14 Correct 389 ms 42392 KB Output is correct
15 Correct 205 ms 37796 KB Output is correct
16 Correct 322 ms 41900 KB Output is correct
17 Correct 207 ms 22520 KB Output is correct