제출 #437361

#제출 시각아이디문제언어결과실행 시간메모리
437361m_bezrutchkaDNA 돌연변이 (IOI21_dna)C++17
100 / 100
70 ms9508 KiB
#include "dna.h" #include <cstdio> #include <algorithm> using namespace std; const int MAXN = 112345; int char_to_int(char c) { if (c == 'A') return 0; if (c == 'C') return 1; return 2; } char int_to_char(int x) { if (x == 0) return 'A'; if (x == 1) return 'C'; return 'T'; } int occur[2][3][MAXN]; int diff[MAXN]; int tot_pairs[3][3][MAXN]; int n; void init(string a, string b) { // printf("%s\n%s\n", a.c_str(), b.c_str()); // printf("init started\n"); n = (int) a.size(); for (int i = 1; i <= n; i++) { for (int k = 0; k < 3; k++) { occur[0][k][i] = occur[0][k][i - 1]; occur[1][k][i] = occur[1][k][i - 1]; for (int r = 0; r < 3; r++) { for (int s = 0; s < 3; s++) { tot_pairs[r][s][i] = tot_pairs[r][s][i - 1]; } } } int val_a = char_to_int(a[i - 1]); occur[0][val_a][i]++; int val_b = char_to_int(b[i - 1]); occur[1][val_b][i]++; tot_pairs[val_a][val_b][i]++; if (val_a != val_b) { diff[i] = diff[i - 1] + 1; } else { diff[i] = diff[i - 1]; } } /* printf("init finished\n"); printf("occur:\n"); for (int s = 0; s < 2; s++) { for (int k = 0; k < 3; k++) { printf("%d %c: ", s, int_to_char(k)); for (int i = 1; i <= n; i++) { printf("%d ", occur[s][k][i]); } printf("\n"); } } printf("diff:\n"); for (int i = 1; i <= n; i++) { printf("%d ", diff[i]); } printf("\n"); printf("tot_pairs:\n"); for (int i = 1; i <= n; i++) { printf("i = %d\n", i); printf(" %c %c %c\n", int_to_char(0), int_to_char(1), int_to_char(2)); for (int r = 0; r < 3; r++) { printf("%c ", int_to_char(r)); for (int s = 0; s < 3; s++) { printf("%d ", tot_pairs[r][s][i]); } printf("\n"); } printf("\n\n"); } */ } int get_distance(int x, int y) { x++; y++; for (int k = 0; k < 3; k++) { int count_a = occur[0][k][y] - occur[0][k][x - 1]; int count_b = occur[1][k][y] - occur[1][k][x - 1]; if (count_a != count_b) { return -1; } } int num_diff = diff[y] - diff[x - 1]; int num_pairs = 0; for (int r = 0; r < 3; r++) { for (int s = r + 1; s < 3; s++) { int r_to_s = tot_pairs[r][s][y] - tot_pairs[r][s][x - 1]; int s_to_r = tot_pairs[s][r][y] - tot_pairs[s][r][x - 1]; num_pairs += min(r_to_s, s_to_r); } } int num_triples = (num_diff - 2 * num_pairs) / 3; // printf("%d %d %d\n", num_diff, num_pairs, num_triples); return num_pairs + 2 * num_triples; }
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