oj.uz

답안 #435859

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
435859 2021-06-23T19:54:43 Z bicsi 사탕 분배 (IOI21_candies) C++17
100 / 100
 4372 ms 9756 KB 
#include "candies.h"
#include <bits/stdc++.h>
 
using namespace std;
using ll = long long;
const int BS = 256;
 
 
vector<ll> compute_function(const vector<int>& ops) {
  vector<ll> stk;
  stk.push_back(4e18);
  stk.push_back(2e18);
  for (auto delta : ops) {
    if (delta == 0) continue;
    if (delta > 0) {
      ll rem = delta, px = 0;
      while (true) {
        ll x = stk.back();
        if (x - px > rem) {
          stk.push_back(px + rem);
          stk.push_back(0);
          break;
        } 
        rem -= (x - px);
        stk.pop_back();
        px = stk.back();
        stk.pop_back();
      }
    } else {
      ll rem = -delta;
      while (true) {
        ll px = stk.back(); stk.pop_back();
        ll x = stk.back();
        if (x - px > rem) {
          stk.push_back(px + rem);
          break;
        }
        rem -= (x - px);
        stk.pop_back();
      }
    }
  }
  
  stk.push_back(0);
  stk.push_back(0);
  reverse(stk.begin(), stk.end());
  return stk;
}
 
vector<int> distribute_candies(
    vector<int> c, vector<int> l,
    vector<int> r, vector<int> v) {
  int n = c.size();
 
  
  // Sort each bucket increasingly by c[i] to facilitate easy evaluation of f.
  vector<int> order(n);
  iota(order.begin(), order.end(), 0);
  for (int i = 0; i < n; i += BS) {
    int j = min(i + BS, n);
    sort(order.begin() + i, order.begin() + j, [&](int a, int b) {
      return c[a] < c[b];
    });
  }
 
  vector<ll> stk;
  vector<int> a(n, 0), na(n, 0);
  vector<vector<int>> ops(n / BS + 1);
 
  auto commit = [&](int bi) {
    if (ops[bi].empty()) return;
    int l = bi * BS, r = min(n, (bi + 1) * BS);
 
    // compute f(.) and evaluate it in all c[i] of this bucket
    auto stk = compute_function(ops[bi]);
    ll value = 0;
    int ptr = 0;
    for (int i = l; i < r; ++i) {
      int ci = c[order[i]];
      while (stk[ptr + 1] < ci) {
        if (ptr % 2 == 0)
          value += stk[ptr + 1] - stk[ptr];
        ++ptr;
      }
      if (ptr % 2 == 0) {
        na[order[i]] = value + (ci - stk[ptr]);
      } else {
        na[order[i]] = value;
      }
    }
  
    // Adapt for non-zero initial values.
    ll mind = 0, maxd = 0, nowd = 0;
    for (auto x : ops[bi]) {
      nowd += x;
      mind = min(mind, nowd);
      maxd = max(maxd, nowd);
    }
    for (int i = l; i < r; ++i) {
      ll hi = min(c[i] - maxd, (ll)a[i]);
      ll lo = -mind;
      if (lo < hi) 
        na[i] += hi - lo; 
    }
 
    // Housekeeping.
    for (int i = l; i < r; ++i) 
      a[i] = na[i];
    ops[bi].clear();
  };
 
  int q = l.size();
  for (int i = 0; i < q; ++i) {
    int bl = l[i] / BS, br = r[i] / BS;
    commit(bl); commit(br); 
    for (int j = l[i]; j <= r[i]; ) {
      if (j % BS == 0 && (j + BS - 1) <= r[i]) {
        ops[j / BS].push_back(v[i]);
        j += BS;
      } else {
        a[j] = max(0, min(a[j] + v[i], c[j]));
        j += 1;
      }
    }
    if (i % BS == 0) 
      for (int i = 0; i < n; i += BS)
        commit(i / BS);
  }
 
  for (int i = 0; i < n; i += BS)
    commit(i / BS);
  return a;
}

Subtask #1
3.0 / 3.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 1 ms 204 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 2 ms 332 KB Output is correct
5 Correct 8 ms 332 KB Output is correct

Subtask #2
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 3703 ms 9620 KB Output is correct
2 Correct 3994 ms 9612 KB Output is correct
3 Correct 3654 ms 9528 KB Output is correct

Subtask #3
27.0 / 27.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 528 ms 5032 KB Output is correct
3 Correct 96 ms 4660 KB Output is correct
4 Correct 2860 ms 9564 KB Output is correct
5 Correct 2744 ms 9672 KB Output is correct
6 Correct 3009 ms 9548 KB Output is correct
7 Correct 2919 ms 9532 KB Output is correct

Subtask #4
29.0 / 29.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 1 ms 204 KB Output is correct
3 Correct 676 ms 5044 KB Output is correct
4 Correct 125 ms 5088 KB Output is correct
5 Correct 4229 ms 9756 KB Output is correct
6 Correct 4170 ms 9752 KB Output is correct
7 Correct 3637 ms 9756 KB Output is correct
8 Correct 4298 ms 9756 KB Output is correct
9 Correct 3554 ms 9756 KB Output is correct

Subtask #5
33.0 / 33.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 1 ms 204 KB Output is correct
3 Correct 1 ms 332 KB Output is correct
4 Correct 2 ms 332 KB Output is correct
5 Correct 8 ms 332 KB Output is correct
6 Correct 3703 ms 9620 KB Output is correct
7 Correct 3994 ms 9612 KB Output is correct
8 Correct 3654 ms 9528 KB Output is correct
9 Correct 1 ms 204 KB Output is correct
10 Correct 528 ms 5032 KB Output is correct
11 Correct 96 ms 4660 KB Output is correct
12 Correct 2860 ms 9564 KB Output is correct
13 Correct 2744 ms 9672 KB Output is correct
14 Correct 3009 ms 9548 KB Output is correct
15 Correct 2919 ms 9532 KB Output is correct
16 Correct 1 ms 204 KB Output is correct
17 Correct 1 ms 204 KB Output is correct
18 Correct 676 ms 5044 KB Output is correct
19 Correct 125 ms 5088 KB Output is correct
20 Correct 4229 ms 9756 KB Output is correct
21 Correct 4170 ms 9752 KB Output is correct
22 Correct 3637 ms 9756 KB Output is correct
23 Correct 4298 ms 9756 KB Output is correct
24 Correct 3554 ms 9756 KB Output is correct
25 Correct 1 ms 204 KB Output is correct
26 Correct 100 ms 4672 KB Output is correct
27 Correct 610 ms 5040 KB Output is correct
28 Correct 4372 ms 9536 KB Output is correct
29 Correct 3970 ms 9632 KB Output is correct
30 Correct 3704 ms 9532 KB Output is correct
31 Correct 3188 ms 9520 KB Output is correct
32 Correct 2986 ms 9540 KB Output is correct