제출 #433304

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
433304		codebuster_10	공장들 (JOI14_factories)	C++17	15 / 100	2703 ms	524292 KiB

factories

#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
 
#define endl "\n"
#define f(i,a,b) for(int i=int(a);i<int(b);++i)
 
#define pr pair
#define ar array
#define fr first
#define sc second
#define vt vector
#define pb push_back
#define eb emplace_back
#define LB lower_bound  
#define UB upper_bound
#define PQ priority_queue
 
#define SZ(x) ((int)(x).size())
#define all(a) (a).begin(),(a).end()
#define allr(a) (a).rbegin(),(a).rend()
#define mem(a,b) memset(a, b, sizeof(a))
 
template<class A> void rd(vt<A>& v);
template<class T> void rd(T& x){ cin >> x; }
template<class H, class... T> void rd(H& h, T&... t) { rd(h) ; rd(t...) ;}
template<class A> void rd(vt<A>& x) { for(auto& a : x) rd(a) ;}
 
template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }
 
template<typename T>
void __p(T a) {
  cout<<a; 
}
template<typename T, typename F>
void __p(pair<T, F> a) {
  cout<<"{";
  __p(a.first);
  cout<<",";
  __p(a.second);
  cout<<"}\n"; 
}
template<typename T>
void __p(std::vector<T> a) {
  cout<<"{";
  for(auto it=a.begin(); it<a.end(); it++)
    __p(*it),cout<<",}\n"[it+1==a.end()]; 
}
template<typename T, typename ...Arg>
void __p(T a1, Arg ...a) {
  __p(a1);
  __p(a...);
}
template<typename Arg1>
void __f(const char *name, Arg1 &&arg1) {
  cout<<name<<" : ";
  __p(arg1);
  cout<<endl;
}
template<typename Arg1, typename ... Args>
void __f(const char *names, Arg1 &&arg1, Args &&... args) {
  int bracket=0,i=0;
  for(;; i++)
    if(names[i]==','&&bracket==0)
      break;
    else if(names[i]=='(')
      bracket++;
    else if(names[i]==')')
      bracket--;
  const char *comma=names+i;
  cout.write(names,comma-names)<<" : ";
  __p(arg1);
  cout<<" | ";
  __f(comma+1,args...);
}
 
void setIO(string s = "") {
  ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); 
  cin.exceptions(cin.failbit); 
	cout.precision(15);	cout << fixed;
  if(SZ(s)){
  	freopen((s+".in").c_str(),"r",stdin);
  	freopen((s+".out").c_str(),"w",stdout);
  }
}
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count());
const long double PI = acos((long double)-1);
 
 
struct custom_hash { /// use most bits rather than just the lowest ones
	const uint64_t C = (long long)(2e18 * PI) + 71; // large odd number
	const int RANDOM = rng();
	long long operator()(long long x) const { /// https://gcc.gnu.org/onlinedocs/gcc/Other-Builtins.html
		return __builtin_bswap64((x^RANDOM)*C); }
};
 
 
template<class K,class V> using hash_table = gp_hash_table<K,V,custom_hash>;
 
 
 
 
 
const long long INF = 1e16;
 
struct edge {
  int node, weight;
  edge(int _node, int _weight) : node(_node), weight(_weight)  {}
};
 
struct centroid_decomposition {
  int N;
  vector<vector<edge>> adj;
  vector<int> depth;
  vector<int> subtree_size;
  // parent of a node in centroid tree.
  vector<int> centroid_parent;
  vector<int> node_list;
  // gives the distance of each node to its descendants in centroid tree.
  vector<hash_table<int, long long>> dis; // from root to node.
 
	
  void init(int _N) {
    N = _N;
    adj.assign(N, {});
    depth.resize(N);
    subtree_size.resize(N);
    centroid_parent.assign(N, -1);
    dis.resize(N);
  }
	
	
  void add_edge(int u, int v, int w) {
    assert(u != v);
    adj[u].emplace_back(edge(v,w));
    adj[v].emplace_back(edge(u,w));
  }
  
  // Erasing edges is O(number of nodes remaining) which is fine within our decomposition.
	void erase_edge(int from, int to) {
		for(edge &e : adj[from]) {
      if(e.node == to) {
        swap(e, adj[from].back());
        adj[from].pop_back();
        return;
      }
    }
    assert(false);
  }
 
  int dfs(int node, int weight = -1, int parent = -1, int root = -1) {
  	if(parent < 0) {
    	root = node;
      node_list.clear();
    }
 
  	if(parent < 0){
  		dis[root][node] = 0;
  	}else{
  		dis[root][node] = (long long)weight + (long long)dis[root][parent];
  	}
  	
    subtree_size[node] = 1;
    node_list.push_back(node);
 
    for(edge &e : adj[node]) {
    	if(e.node != parent) {
      	subtree_size[node] += dfs(e.node, e.weight, node, parent < 0 ? node : root);
      }
    }
 
    return subtree_size[node];
  }
 
  int centroid(int root) {
  	int n = dfs(root);
    bool found;
 
    // Repeatedly move to the subtree that is at least half of the tree, if such a subtree exists.
    do {
      found = false;
 
      for(edge &e : adj[root]){
        if(subtree_size[e.node] < subtree_size[root] && 2 * subtree_size[e.node] >= n) {
          root = e.node;
          found = true;
          break;
      	}
      }
    } while(found);
 
    return root;
  }
 
	// centroid parent of root of centroid tree is -1
  void solve(int root) {
  	root = centroid(root);
    dfs(root);
 
    for(int node : node_list){
      if(node != root){
         centroid_parent[node] = root;
			}
    }
 
  	for(edge &e : adj[root]){
    	erase_edge(e.node, root);
    }
 
  	// Recurse after solving root, so that edge erasures don't cause incorrect results.
    for(edge &e : adj[root]){
      solve(e.node);
    }
  }
}cd;
 
 
vt<long long> ans;
 
 
void turn_on(int _i){
	for(int i = _i; ~i; i = cd.centroid_parent[i]){
		ckmin(ans[i],cd.dis[i][_i]);
	}
}
 
void turn_off(int _i){
	for(int i = _i; ~i; i = cd.centroid_parent[i]){
		ans[i] = INF;
	}
}
 
 
 
 
 
 
 
 
 
 
void Init(int N, int A[], int B[], int D[]) {
	cd.init(N);
	ans.assign(N,INF);
	f(e,0,N-1){
		cd.add_edge(A[e],B[e],D[e]);
	}
	cd.solve(0);
	return;
}
 
 
long long Query(int S, int X[], int T, int Y[]) {
	
	f(i,0,S) turn_on(X[i]);
	
	long long res = INF;
	f(i,0,T){
		for(int j = Y[i]; ~j; j = cd.centroid_parent[j]){
			ckmin(res, cd.dis[j][Y[i]] + ans[j]);
		}
	}
	
	
	
	f(i,0,S) turn_off(X[i]);
	
  return res;
}

 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
/*
 
 
 
 
#include <stdio.h>
#include <stdlib.h>
 
#define MAX_N          500000
#define MAX_Q          100000
#define MAX_SUM_ST    1000000
#define MAX_VALUE  1000000000
 
static int N, Q;
static int A[MAX_N], B[MAX_N], D[MAX_N];
static int S[MAX_N];
static int T[MAX_N];
static int X[MAX_SUM_ST];
static int Y[MAX_SUM_ST];
 
static int Qx[MAX_N];
static int Qy[MAX_N];
 
int main() {
 
  int i, j, k;
  int STop, TTop;
 
  if (2 != scanf("%d%d", &N, &Q)) {
    fprintf(stderr, "error: cannot read N and Q.\n");
    exit(1);
  }
  if (!(2 <= N && N <= MAX_N)) {
    fprintf(stderr, "error: N is out of bounds.\n");
    exit(1);
  }
  if (!(1 <= Q && Q <= MAX_Q)) {
    fprintf(stderr, "error: Q is out of bounds.\n");
    exit(1);
  }
  for (i = 0; i < N - 1; ++i) {
    if (1 != scanf("%d", &A[i])) {
      fprintf(stderr, "error: cannot read A[%d].\n", i);
      exit(1);
    }
    if (!(0 <= A[i] && A[i] <= N - 1)) {
      fprintf(stderr, "error: A[%d] is out of bounds.\n", i);
      exit(1);
    }
    if (1 != scanf("%d", &B[i])) {
      fprintf(stderr, "error: cannot read B[%d].\n", i);
      exit(1);
    }
    if (!(0 <= B[i] && B[i] <= N - 1)) {
      fprintf(stderr, "error: B[%d] is out of bounds.\n", i);
      exit(1);
    }
    if (A[i] == B[i]) {
      fprintf(stderr, "error: B[%d] is equal to A[%d].\n", i, i);
      exit(1);
    }
    if (1 != scanf("%d", &D[i])) {
      fprintf(stderr, "error: cannot read D[%d].\n", i);
      exit(1);
    }
    if (!(1 <= D[i] && D[i] <= MAX_VALUE)) {
      fprintf(stderr, "error: D[%d] is out of bounds.\n", i);
      exit(1);
    }
  }
 
  STop = 0;
  TTop = 0;
 
  for (j = 0; j < Q; ++j) {
    if (2 != scanf("%d%d", &S[j], &T[j])) {
      fprintf(stderr, "error: cannot read L[%d] and R[%d].\n", j, j);
      exit(1);
    }
 
    if(STop + S[j] > MAX_SUM_ST) {
      fprintf(stderr, "error: S[0] + S[1] + ... + S[%d] is out of bounds.\n", j);
      exit(1);
    }
 
    if(TTop + T[j] > MAX_SUM_ST) {
      fprintf(stderr, "error: T[0] + T[1] + ... + T[%d] is out of bounds.\n", j);
      exit(1);
    }
 
    for (k = 0; k < S[j]; ++k, ++STop) {
      if (1 != scanf("%d", &X[STop])) {
        fprintf(stderr, "error: cannot read X[%d][%d].\n", j, k);
        exit(1);
      }
 
      if (!(0 <= X[STop] && X[STop] <= N - 1)) {
        fprintf(stderr, "error: cannot read X[%d][%d].\n", j, k);
        exit(1);
      }
    }
 
    for (k = 0; k < T[j]; ++k, ++TTop) {
      if (1 != scanf("%d", &Y[TTop])) {
        fprintf(stderr, "error: cannot read Y[%d][%d].\n", j, k);
        exit(1);
      }
 
      if (!(0 <= Y[TTop] && Y[TTop] <= N - 1)) {
        fprintf(stderr, "error: cannot read Y[%d][%d].\n", j, k);
        exit(1);
      }
    }
  }
 
  STop = 0;
  TTop = 0;
  Init(N, A, B, D);
 
  for (j = 0; j < Q; ++j) {
    for (k = 0; k < S[j]; k++) {
        Qx[k] = X[STop++];
    }
    for (k = 0; k < T[j]; k++) {
        Qy[k] = Y[TTop++];
    }
 
    printf("%lld\n", Query(S[j], Qx, T[j], Qy));
  }
 
 
  return 0;
}
 
 
 
 
 
 
 
 */
 
 
 
 
 
 
 
 
 
 
 

컴파일 시 표준 에러 (stderr) 메시지

factories.cpp: In function 'void setIO(std::string)':
factories.cpp:84:11: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   84 |    freopen((s+".in").c_str(),"r",stdin);
      |    ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~
factories.cpp:85:11: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   85 |    freopen((s+".out").c_str(),"w",stdout);
      |    ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 15 / 15
• Subtask 2: 0 / 18
• Subtask 3: 0 / 67