oj.uz

답안 #426273

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
426273 2021-06-13T16:31:40 Z wiwiho 낙하산 고리들 (IOI12_rings) C++14
0 / 100
 2019 ms 103448 KB 
#include <bits/stdc++.h>
#include <bits/extc++.h>

#define StarBurstStream ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define iter(a) a.begin(), a.end()
#define riter(a) a.rbegin(), a.rend()
#define lsort(a) sort(iter(a))
#define gsort(a) sort(riter(a))
#define pb(a) push_back(a)
#define eb(a) emplace_back(a)
#define pf(a) push_front(a)
#define ef(a) emplace_front(a)
#define pob pop_back()
#define pof pop_front()
#define mp(a, b) make_pair(a, b)
#define F first
#define S second
#define mt make_tuple
#define gt(t, i) get<i>(t)
#define tomax(a, b) ((a) = max((a), (b)))
#define tomin(a, b) ((a) = min((a), (b)))
#define topos(a) ((a) = (((a) % MOD + MOD) % MOD))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define printv(a, b) {bool pvaspace=false; \
for(auto pva : a){ \
    if(pvaspace) b << " "; pvaspace=true;\
    b << pva;\
}\
b << "\n";}

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;
using tiii = tuple<int, int, int>;

const ll MOD = 1000000007;
const ll MAX = 2147483647;

template<typename A, typename B>
ostream& operator<<(ostream& o, pair<A, B> p){
    return o << '(' << p.F << ',' << p.S << ')';
}

ll ifloor(ll a, ll b){
    if(b < 0) a *= -1, b *= -1;
    if(a < 0) return (a - b + 1) / b;
    else return a / b;
}

ll iceil(ll a, ll b){
    if(b < 0) a *= -1, b *= -1;
    if(a > 0) return (a + b - 1) / b;
    else return a / b;
}

int n = -1;
vector<pii> edge;
vector<vector<int>> g;

struct DSU{
    vector<int> dsu;
    vector<int> deg, cnt, one, sz;
    int cycle = -1;
    int con = 0;
    void init(){
        con = n;
        cnt.resize(4);
        dsu.resize(n);
        deg.resize(n);
        one.resize(n);
        sz.resize(n, 1);
        cnt[0] = n;
        for(int i = 0; i < n; i++) dsu[i] = i;
    }
    int findDSU(int a){
        if(dsu[a] != a) dsu[a] = findDSU(dsu[a]);
        return dsu[a];
    }
    void unionDSU(int a, int b){
        int pa = findDSU(a);
        int pb = findDSU(b);
        if(deg[a] == 1) one[pa]--;
        if(deg[b] == 1) one[pb]--;
        cnt[min(deg[a], 3)]--;
        cnt[min(deg[b], 3)]--;
        if(pa != pb){
            dsu[pb] = pa;
            con--;
            one[pa] += one[pb];
            sz[pa] += sz[pb];
        }
        deg[a]++; deg[b]++;
        if(deg[a] == 1) one[pa]++;
        if(deg[b] == 1) one[pa]++;
        cnt[min(deg[a], 3)]++;
        cnt[min(deg[b], 3)]++;
        if(sz[pa] > 1 && one[pa] == 0) cycle = sz[pa];
    }
    bool ok(){
        return cnt[3] == 0 && cnt[1] == (con - cnt[0]) * 2;
    }
    int cy(){
        if(deg[3] != 0 || deg[1] + 2 != (con - deg[0]) * 2) return -1;
        return cycle;
    }
    void print(){
        cerr << "DSU " << ok() << " " << cy() << " " << con << "\n";
        cerr << "dsu: ";
        printv(dsu, cerr);
        cerr << "sz: ";
        printv(sz, cerr);
        cerr << "cnt: ";
        printv(cnt, cerr);
        cerr << "deg: ";
        printv(deg, cerr);
    }
};

struct OAO{
    int no;
    DSU dsu;
    explicit OAO(int no = -1): no(no) {
        if(n != -1) dsu.init();
        for(pii p : edge){
            addedge(p.F, p.S);
        }
    }
    void addedge(int u, int v){
        if(u == no || v == no) return;
        dsu.unionDSU(u, v);
    }
};

OAO all;
vector<OAO> oao;
int status = 0;

void neighbor(int v){
    if(status >= 1) return;
    status = 1;
    oao.clear();
    oao.eb(OAO(v));
    for(int i : g[v]) oao.eb(OAO(i));
}

void only(int v){
    if(status >= 2) return;
    status = 2;
    oao.clear();
    oao.eb(OAO(v));
}

void addedge(int u, int v){
    g[u].eb(v);
    g[v].eb(u);
    edge.eb(mp(u, v));
    all.addedge(u, v);
    for(OAO& oao : oao) oao.addedge(u, v);
    if(g[u].size() == 3) neighbor(u);
    if(g[u].size() == 4) only(u);
    if(g[v].size() == 3) neighbor(v);
    if(g[v].size() == 4) only(v);
}

void Init(int N){
    n = N;
    all.dsu.init();
    g.resize(n);
}

void Link(int u, int v){
    addedge(u, v);
}

int CountCritical(){
//    cerr << "test\n";
//    all.dsu.print();
//    for(OAO& t : oao){
//        cerr << "test " << t.no << "\n";
//        t.dsu.print();
//    }
    if(all.dsu.ok()) return n;
    else if(all.dsu.cy() != -1) return all.dsu.cy();
    int ans = 0;
    for(OAO& t : oao) ans += t.dsu.ok();
    return ans;
}

Subtask #1
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 4 ms 844 KB Output is correct
3 Correct 3 ms 844 KB Output is correct
4 Incorrect 1 ms 332 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 17.0

# 결과 실행 시간 메모리 Grader output
1 Correct 562 ms 47980 KB Output is correct
2 Correct 1803 ms 103448 KB Output is correct
3 Correct 2019 ms 103364 KB Output is correct
4 Incorrect 1513 ms 91884 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #3
0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 4 ms 844 KB Output is correct
3 Correct 3 ms 844 KB Output is correct
4 Incorrect 1 ms 332 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #4
0 / 14.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 4 ms 844 KB Output is correct
3 Correct 3 ms 844 KB Output is correct
4 Incorrect 1 ms 332 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #5
0 / 31.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 204 KB Output is correct
2 Correct 4 ms 844 KB Output is correct
3 Correct 3 ms 844 KB Output is correct
4 Incorrect 1 ms 332 KB Output isn't correct
5 Halted 0 ms 0 KB -