Submission #420808

#TimeUsernameProblemLanguageResultExecution timeMemory
420808QCFiumSplit the Attractions (IOI19_split)C++14
0 / 100
3 ms332 KiB
#include <bits/stdc++.h>

int ri() {
	int n;
	scanf("%d", &n);
	return n;
}

static std::vector<std::vector<int> > hen;

std::vector<int> find_split(int n, int a, int b, int c, std::vector<int> p, std::vector<int> q) {
	hen.resize(n);
	for (int i = 0; i < (int) p.size(); i++) {
		hen[p[i]].push_back(q[i]);
		hen[q[i]].push_back(p[i]);
	}
	std::vector<int> res(n, -1);
	if (a == 1) {
		std::vector<bool> visited(n);
		std::queue<int> que;
		que.push(0);
		visited[0] = true;
		std::vector<int> group2;
		while (que.size()) {
			auto i = que.front();
			que.pop();
			group2.push_back(i);
			if ((int) group2.size() == b) break;
			for (auto j : hen[i]) if (!visited[j]) visited[j] = true, que.push(j);
		}
		for (auto i : group2) res[i] = 2;
		*std::find(res.begin(), res.end(), -1) = 1;
		for (auto &i : res) if (i == -1) i = 3;
	}
	
}

#ifdef LOCAL
int main() {
	
	return 0;
}
#endif

Compilation message (stderr)

split.cpp: In function 'std::vector<int> find_split(int, int, int, int, std::vector<int>, std::vector<int>)':
split.cpp:36:1: warning: no return statement in function returning non-void [-Wreturn-type]
   36 | }
      | ^
split.cpp: In function 'int ri()':
split.cpp:5:7: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
    5 |  scanf("%d", &n);
      |  ~~~~~^~~~~~~~~~
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