이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "highway.h"
#include <bits/stdc++.h>
#define eb emplace_back
#define printv(a, b) { \
for(auto pv : a) b << pv << " "; \
b << "\n"; \
}
#define mp make_pair
#define F first
#define S second
#define pob pop_back()
#define iter(a) a.begin(), a.end()
using namespace std;
typedef long long ll;
using pll = pair<ll, ll>;
using pii = pair<int, int>;
int n;
int m;
vector<vector<pii>> g;
vector<int> pr, pre, dpt;
ll query(int rt, int to){
vector<int> q(m);
while(to != rt){
q[pre[to]] = 1;
to = pr[to];
}
return ask(q);
}
ll query(int rt, int l, int r, vector<int>& v){
vector<int> q(m);
vector<int> tos;
for(int i = l; i <= r; i++) tos.eb(v[i]);
for(int to : tos){
while(to != rt){
q[pre[to]] = 1;
to = pr[to];
}
}
return ask(q);
}
ll querye(int l, int r){
vector<int> q(m);
for(int i = l; i <= r; i++) q[i] = 1;
return ask(q);
}
vector<int> vst;
void dfs(int now, int p, int e, int d, int no){
pr[now] = p;
pre[now] = e;
dpt[now] = d;
vst.eb(now);
for(pii i : g[now]){
if(i.F == p || i.S == no) continue;
dfs(i.F, now, i.S, d + 1, no);
}
}
void find_pair(int N, vector<int> U, vector<int> V, int a, int b) {
n = N;
m = U.size();
assert(m == n - 1);
g.resize(n);
pr.resize(n);
pre.resize(n);
dpt.resize(n);
for(int i = 0; i < m; i++){
int u = U[i], v = V[i];
g[u].eb(mp(v, i));
g[v].eb(mp(u, i));
}
vector<int> XD(m);
ll dis = ask(XD);
//cerr << dis << "\n";
int l = 0, r = m - 1;
while(l < r){
int mid = (l + r) / 2;
if(querye(l, mid) != dis) r = mid;
else l = mid + 1;
}
int e = l;
dfs(U[e], U[e], -1, 0, e);
ll dis1 = query(U[e], 0, (int)vst.size() - 1, vst);
int len1 = (dis1 - dis) / (b - a);
vector<int> tmp;
for(int i : vst) if(dpt[i] == len1) tmp.eb(i);
l = 0; r = (int)tmp.size() - 1;
while(l < r){
int mid = (l + r) / 2;
if(query(U[e], l, mid, tmp) == dis1) r = mid;
else l = mid + 1;
}
int v1 = tmp[l];
vst.clear();
dfs(V[e], V[e], -1, 0, e);
ll dis2 = query(V[e], 0, (int)vst.size() - 1, vst);
int len2 = (dis2 - dis) / (b - a);
tmp.clear();
for(int i : vst) if(dpt[i] == len2) tmp.eb(i);
l = 0; r = (int)tmp.size() - 1;
while(l < r){
int mid = (l + r) / 2;
if(query(V[e], l, mid, tmp) == dis2) r = mid;
else l = mid + 1;
}
int v2 = tmp[l];
//cerr << e << " " << U[e] << " " << V[e] << " " << v1 << " " << v2 << "\n";
answer(v1, v2);
}
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