제출 #397437

#제출 시각아이디문제언어결과실행 시간메모리
397437phathnv푸드 코트 (JOI21_foodcourt)C++11
100 / 100
888 ms45220 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; const int N = 25e4 + 7; struct Query{ int t, l, r, c; ll k; }; struct Node{ ll val; Node *Left, *Right; Node(ll _val){ val = _val; Left = Right = nullptr; } }; struct BIT{ ll d[N]; void update(int x, int val){ for(; x < N; x += x & -x) d[x] += val; } ll get(int x){ ll res = 0; for(; x > 0; x -= x & -x) res += d[x]; return res; } void updateRange(int l, int r, int val){ update(l, val); update(r + 1, -val); } } bit; struct SegTree{ int n; ll d[N * 4], lazyVal[N * 4], lazyMax[N * 4]; void init(int _n){ n = _n; } void doLazy(int id, int l, int r){ d[id] += lazyVal[id]; d[id] = max(d[id], lazyMax[id]); if (l < r){ lazyVal[id << 1] += lazyVal[id]; lazyMax[id << 1] += lazyVal[id]; lazyMax[id << 1] = max(lazyMax[id << 1], lazyMax[id]); lazyVal[id << 1 | 1] += lazyVal[id]; lazyMax[id << 1 | 1] += lazyVal[id]; lazyMax[id << 1 | 1] = max(lazyMax[id << 1 | 1], lazyMax[id]); } lazyVal[id] = lazyMax[id] = 0; } void update(int id, int l, int r, int u, int v, int val){ doLazy(id, l, r); if (v < l || r < u) return; if (u <= l && r <= v){ lazyVal[id] += val; doLazy(id, l, r); return; } int mid = (l + r) >> 1; update(id << 1, l, mid, u, v, val); update(id << 1 | 1, mid + 1, r, u, v, val); } ll get(int id, int l, int r, int pos){ doLazy(id, l, r); if (pos < l || r < pos) return 0; if (l == r) return d[id]; int mid = (l + r) >> 1; return max(get(id << 1, l, mid, pos), get(id << 1 | 1, mid + 1, r, pos)); } void update(int l, int r, int k){ update(1, 1, n, l, r, k); } ll get(int pos){ return get(1, 1, n, pos); } } st; struct SegTreeMin{ int n; ll d[N * 4], lazy[N * 4]; void init(int _n){ n = _n; } void doLazy(int id, int l, int r){ d[id] += lazy[id]; if (l < r){ lazy[id << 1] += lazy[id]; lazy[id << 1 | 1] += lazy[id]; } lazy[id] = 0; } void update(int id, int l, int r, int u, int v, ll val){ doLazy(id, l, r); if (v < l || r < u) return; if (u <= l && r <= v){ lazy[id] += val; doLazy(id, l, r); return; } int mid = (l + r) >> 1; update(id << 1, l, mid, u, v, val); update(id << 1 | 1, mid + 1, r, u, v, val); d[id] = min(d[id << 1], d[id << 1 | 1]); } int findPos(int id, int l, int r){ doLazy(id, l, r); if (d[id] > 0) return -1; if (l == r) return l; int mid = (l + r) >> 1; int res = findPos(id << 1, l, mid); if (res == -1) res = findPos(id << 1 | 1, mid + 1, r); return res; } void update(int l, int r, ll val){ update(1, 1, n, l, r, val); } int findPos(){ return findPos(1, 1, n); } } stMin; int n, m, q, answer[N]; Query queries[N]; vector<pair<ll, int>> data[N]; int main(){ ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> m >> q; for(int i = 1; i <= q; i++){ cin >> queries[i].t; if (queries[i].t == 1) cin >> queries[i].l >> queries[i].r >> queries[i].c >> queries[i].k; else if (queries[i].t == 2) cin >> queries[i].l >> queries[i].r >> queries[i].k; else cin >> queries[i].l >> queries[i].k; } st.init(n); for(int i = 1; i <= q; i++) if (queries[i].t == 1) { st.update(queries[i].l, queries[i].r, queries[i].k); bit.updateRange(queries[i].l, queries[i].r, queries[i].k); } else if (queries[i].t == 2) { st.update(queries[i].l, queries[i].r, -queries[i].k); } else { if (st.get(queries[i].l) < queries[i].k){ answer[i] = 0; } else { ll x = bit.get(queries[i].l) - (st.get(queries[i].l) - queries[i].k); data[queries[i].l].push_back({x, i}); } } stMin.init(n); for(int i = 1; i <= n; i++){ sort(data[i].begin(), data[i].end(), greater<pair<ll, int>>()); if (data[i].empty()) stMin.update(i, i, 1e18); else stMin.update(i, i, data[i].back().first); } for(int i = 1; i <= q; i++) if (queries[i].t == 1){ stMin.update(queries[i].l, queries[i].r, -queries[i].k); while (stMin.findPos() != -1){ int pos = stMin.findPos(); answer[data[pos].back().second] = queries[i].c; ll pre = data[pos].back().first; data[pos].pop_back(); if (data[pos].empty()) stMin.update(pos, pos, 1e18); else stMin.update(pos, pos, data[pos].back().first - pre); } } for(int i = 1; i <= q; i++) if (queries[i].t == 3) cout << answer[i] << '\n'; return 0; }
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