제출 #397018

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
397018		IloveN	앵무새 (IOI11_parrots)	C++14	0 / 100	291 ms	262148 KiB

encoder

#include<bits/stdc++.h>
#include "encoder.h"
#include "encoderlib.h"

using namespace std;
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define all(vr) vr.begin(),vr.end()
#define vi vector<int>
#define vll vector<ll>
const int N = 1e5 + 10;

ll C[42][42];

void build()
{
    for (int i = 0; i <= 40; ++i)
    {
        C[0][i] = 1;
        for (int j = 2 ; j <= i; ++j) C[j][i] = C[j - 1][i - 1] + C[j][i - 1];
    }
}

vi find_kth(ll k, int d)
{
    vi ans;
    int s = d * 5;
    for (int i = 0 ; i < 16; ++i)
    {
        ll sl = C[15 - i][s + 15 - i];
        while (k >= sl) k -= sl, s--, ans.eb(i);
    }
    return ans;
}

void encode(int n, int M[])
{
    build();
    for (int i = 0; i < n; i += 4)
    {
        ll s = 0;
        int d = 0;
        for (int j = i; j < min(n, i + 4); ++j) d++, s = (s << 8) + M[j];
        vi vt = find_kth(s, d);
        for (int x : vt) send((x << 4) + (i / 4));
    }
}

decoder

#include<bits/stdc++.h>
#include "decoder.h"
#include "decoderlib.h"

using namespace std;
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define all(vr) vr.begin(),vr.end()
#define vi vector<int>
#define vll vector<ll>
const int N = 1e5 + 10;

ll C[42][42];

void build()
{
    for (int i = 0; i <= 40; ++i)
    {
        C[0][i] = 1;
        for (int j = 2 ; j <= i; ++j) C[j][i] = C[j - 1][i - 1] + C[j][i - 1];
    }
}

int a[20][20];

ll find_order(int cnt[], int d)
{
    ll k = 0;
    int s = d * 5;
    for (int i = 0 ; i < 16; ++i)
    {
        ll sl = C[15 - i][s + 15 - i];
        for (int j = 0 ; j < cnt[i]; ++j) k += sl, s--;
    }
    return k;
}

void decode(int n, int L, int X[])
{
    build();
    for (int i = 0; i < 16; ++i)
        for (int j = 0; j < 16; ++j) a[i][j] = 0;
    for (int i = 0; i < L; ++i) a[X[i] & 15][X[i] >> 4]++;
    for (int i = 0; i < n; i += 4)
    {
        int d = min(4, n - i), id  = i / 4;
        ll k = find_order(a[id], d);
        vi vt;
        for (int j = 0; j < d; ++j) vt.eb(k & 255), k >>= 8;
        reverse(all(vt));
        for (int x : vt) output(x);
    }
}

• Subtask 1: 0 / 17
• Subtask 2: 0 / 17
• Subtask 3: 0 / 18
• Subtask 4: 0 / 29
• Subtask 5: 0 / 19