이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <algorithm>
#include <vector>
#include <map>
#include <set>
#include <array>
#include <stack>
#include <queue>
#include <random>
#include <numeric>
#include <functional>
#include <chrono>
#include <utility>
#include <iomanip>
#include <assert.h>
using namespace std;
void dbg_out() { cerr << endl; }
template<typename Head, typename... Tail>
void dbg_out(Head H, Tail... T) { cerr << ' ' << H; dbg_out(T...); }
#define dbg(...) cerr << "(" << #__VA_ARGS__ << "):", dbg_out(__VA_ARGS__)
#define rng_init mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())
#define rng_seed(x) mt19937 rng(x)
#define all(x) (x).begin(), (x).end()
#define sz(x) (int) (x).size()
#define int long long
const int MXN = 1e5 + 5, INF = 1e18;
int N, K;
int A[MXN], dp[2][MXN], pref[MXN], trace[205][MXN];
void dnc(int l, int r, int i, int optl, int optr) {
if (l > r) return;
int cur = i & 1;
int mid = (l + r) / 2;
pair<int, int> best = {-INF, -INF};
for (int j = optl; j < min(mid, optr + 1); j++) {
int new_val = dp[cur ^ 1][j] + (pref[mid] - pref[j]) * (pref[N] - pref[mid]);
if (new_val > best.first)
best = make_pair(new_val, j);
}
dp[cur][mid] = best.first;
trace[i][mid] = best.second;
dnc(l, mid - 1, i, optl, best.second);
dnc(mid + 1, r, i, best.second, optr);
}
void solve() {
cin >> N >> K;
for (int i = 1; i <= N; i++) {
cin >> A[i];
pref[i] = pref[i - 1] + A[i];
}
for (int i = 0; i < 2; i++)
for (int j = 0; j < MXN; j++)
dp[i][j] = -INF;
dp[0][0] = 0;
for (int i = 1; i <= K; i++)
dnc(i, N, i, i - 1, N - 1);
pair<int, int> best = {-INF, -INF};
for (int j = 1; j < N; j++)
best = max(best, make_pair(dp[K & 1][j], j));
cout << best.first << "\n";
int cur_k = K;
while (cur_k) {
cout << best.second << " ";
best.second = trace[cur_k--][best.second];
}
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int TC = 1;
// cin >> TC;
while (TC--) solve();
}
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