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답안 #392832

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
392832 2021-04-21T21:30:34 Z SirCovidThe19th Burza (COCI16_burza) C++14
0 / 160
 18 ms 22476 KB 
#include <bits/stdc++.h>
using namespace std;

int n, k;

vector<int> intervalL;
vector<int> intervalR;
vector<int> depth;

vector<vector<int>> adjList;
vector<vector<int>> check;
int track = 0;

void dfs(int node, int parent){
    if (depth[node] == k){
        intervalL[node] = track;
        intervalR[node] = track;
        track++;
    }
    else{
        for (int child : adjList[node]){
            if (child == parent) continue;
            depth[child] = depth[node]+1;
            dfs(child, node);
            intervalL[node] = min(intervalL[child], intervalL[node]);
            intervalR[node] = max(intervalR[child], intervalR[node]);
        }
    }
    if (node != 0 and intervalR[node] != -1){
        check[intervalR[node]].push_back(node);
    }
}
int main(){

    cin >> n >> k;
    adjList.resize(n);
    depth.resize(n);
    intervalL.resize(n);
    intervalR.resize(n);
    check.resize(n);

    depth[0] = 0;
    fill(intervalL.begin(), intervalL.end(), 1000000007);
    fill(intervalR.begin(), intervalR.end(), -1);

    for (int i = 0; i < n-1; i++){
        int a, b;
        cin >> a >> b;
        adjList[a-1].push_back(b-1);
        adjList[b-1].push_back(a-1);
    }
    if (k*k >= n){
        cout<<"DA";
        return 0;
    }
    dfs(0, 0);
    bool valid = false;
    //dp[i][j] - can we use only nodes of depths in subset i such 
    //that we cannot get to the first j(0 index) nodes at depth K
    bool dp[(1<<k)][track];
    memset(dp, false, sizeof(dp));
    for (int i = 1; i < (1<<k); i++){
        //can we fill interval [1, j]
        for (int j = 0; j < track; j++){
            //go through all points going to j
            for (int node : check[j]){
                //make sure depth is in subset
                if ((i&((1<<depth[node])-1)) != 0){
                    dp[i][j] = dp[i][j] or (dp[i^(1<<depth[node])][intervalL[node]]);
                }
            }
        }
        if (dp[i][track-1])
            valid = true;
    }
    if (valid)
        cout<<"DA";
    else
        cout<<"NE";
    
}

Subtask #1
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 3 ms 3532 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #2
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 17 ms 21480 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #3
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 17 ms 21192 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #4
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 7 ms 8524 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #5
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 14 ms 18124 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #6
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 18 ms 22476 KB Execution killed with signal 7
2 Halted 0 ms 0 KB -

Subtask #7
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 18 ms 21712 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #8
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 6 ms 6348 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #9
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 3 ms 2636 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -

Subtask #10
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Runtime error 9 ms 8400 KB Execution killed with signal 11
2 Halted 0 ms 0 KB -