제출 #388450

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
388450		JimmyZJX	비스킷 담기 (IOI20_biscuits)	C++14	0 / 100	1086 ms	332 KiB

biscuits

#include <iostream>
#include <fstream>
#include <algorithm>
#include <cstring>
#include <climits>
#include <cassert>
#include <tuple>
#include <queue>
#include <stack>
#include <vector>
#include <map>
#include <set>
#include <string>

using namespace std;

typedef long long LL;
typedef vector<int> Vi;
typedef vector<LL> VL;
typedef vector<bool> Vb;
typedef vector<vector<int>> Vii;

#define MAXP 61

#define forR(i, n) for (int i = 0; i < (n); i++)

VL preSum(MAXP);

LL count(LL x, VL a, int p) {
	// [ 0, 2^p ) ++ [ 2^p , 2^(p+1) )

	if (p == 0) {
		return a[0] >= x ? 2 : 1;
	}

	LL count_before_p = count(x, a, p - 1);

	if (a[p] >= x) {
		return 2 * count_before_p;
	} else if (p > 0 && a[p] + (preSum[p - 1] >> p) >= x) {
		LL rest = (x - a[p]) * (1LL << p);
		for (int c = p - 1; c >= 0 && rest > 0; c--) {
			LL cnt = min(a[c], rest / (1LL << c));
			rest -= cnt * (1LL << c);
			a[c] -= cnt;
		}
		assert(rest == 0);

		LL chooseP = 0;
		auto preSumBackup = preSum;
		{
			forR(i, p) {
				preSum[i] = i > 0 ? preSum[i - 1] : 0;
				preSum[i] += ((LL)1 << i) * a[i];
			}
			chooseP = count(x, a, p - 1);
		}
		preSum = preSumBackup;
		return count_before_p + chooseP;
	} else {
		return count_before_p;
	}
}

LL count_tastiness(LL x, VL a) {
	int k = a.size();
	a.resize(MAXP);

	LL c = 0;
	forR(i, MAXP) {
		a[i] += c;
		if (a[i] > x) {
			c = (a[i] - x) / 2;
			a[i] -= c * 2;
		}
	}

	forR(i, MAXP) {
		preSum[i] = i > 0 ? preSum[i - 1] : 0;
		preSum[i] += ((LL)1 << i) * a[i];
	}

	return count(x, a, MAXP - 1);
}


#ifdef TEST_LOCAL
int main() {
	LL res;
	res = count_tastiness(3, VL{ 5,2,1 });
	res = count_tastiness(2, VL{ 2,1,2 });

	return 0;
}
#endif

컴파일 시 표준 에러 (stderr) 메시지

biscuits.cpp: In function 'LL count_tastiness(LL, VL)':
biscuits.cpp:66:6: warning: unused variable 'k' [-Wunused-variable]
   66 |  int k = a.size();
      |      ^

• Subtask 1: 0 / 9
• Subtask 2: 0 / 12
• Subtask 3: 0 / 21
• Subtask 4: 0 / 35
• Subtask 5: 0 / 23